Questions tagged [improper-integrals]

Questions involving improper integrals, defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

An improper integral is defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

Specifically, an improper integral is a limit of the form:

$$\lim_{b\to \infty} \int_{a}^{b} f(x) \ dx \,,\ \lim_{a \to -\infty} \int_{a}^{b} f(x) \ dx$$ or of the form $$\lim_{c \to b^{-}} \int_{a}^{c} f(x) \ dx \,,\ \lim_{c \to a^{+}} \int_{c}^{b} f(x) \ dx$$

in which one takes a limit in one or the other (or sometimes both) endpoints.

Often, we can compute values for improper integrals, even when the function cannot be integrated in the conventional sense (as a Riemann integral, for instance), because of a singularity in the function or because one of the bounds of integration is infinite.

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Improper integral ???

Hello everyone,i'm trying to solve this problem: For what values $a$ and $b$ is $$ \int_{\frac{1}{\pi}}^{\infty} x^{a}[\sin\frac{1}{x}]^{b}dx $$ convergent??? So i tried like this: using the $ x=1/t$, integral becomes $$ \int_{0}^{\pi}…
Zoran
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Help! Improper integral convergence (values of P)

I'm quite lost on the following problem: $$\int_{0}^{\pi/2} \frac{sin^2(x)}{x^{p^2-3p-7}}dx$$ I can't figure out how to work out the given answer. Please help me!
ZellAllon
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Improper integral when the integrand goes to infinity.

Is it true that if $$\lim_{x\to +\infty} f(x)=+\infty$$ then $f $ can not be integrable at the neighborhood of $+\infty$, hence the improper integral $\int_0^{+\infty}{f(x)dx}$ does not exist?
palio
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Is there a smooth function with an asymptote at zero and integrable over $]0,\infty[$?

If you look at functions of the form $1/x^k$, $k>0$, it seems you can't have your cake and eat it too. If the integral of $1/x^k$ converges on $[1,\infty[$, then it diverges on $]0,1]$ and vice-versa, and if you try to balance things by picking…
user46242
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Is it possible to compute $\int_1^{+ \infty} \frac{dx}{x^2(1+e^x)}$?

Essentially, all is in the title: Is it possible to compute the integral $$\int_1^{+ \infty} \frac{dx}{x^2(1+e^x)} \hspace{1cm} ?$$ I suspected some relation with a polygamma function, but I was not able to find something explicit.
Seirios
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how to use comparison test for improper integral?

I should determine whether this is a convergent or divergent integral. i need to use the comparison test but i don't know where to start. there is a method to find the integral we need to compare to? how to start? $$ \int_{0}^{1}…
user2637293
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Convergence (absolutely) of an improper integral $\int_{-\infty}^\infty\frac{\sin(\sin x)}{1+\log(\lfloor|x|\rfloor! + 2)} dx$

$$\int_{-\infty}^\infty\frac{\sin(\sin x)}{1+\log(\lfloor|x|\rfloor! + 2)} dx$$ I need to check if this integral is absolutely convergent... I've shown it's convergent (not absolutely), according dirichlet test. I think it's conditionally…
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improper integral $\int_{0}^{\infty}\frac{2x}{e^{x}-e^{-x}}dx$

I have a problem with my solution. $$\int_{0}^{\infty}\frac{2x}{e^{x}-e^{-x}}dx=\int_{0}^{a}\frac{2x}{e^{x}-e^{-x}}dx+\int_{a}^{\infty}\frac{2x}{e^{x}-e^{-x}}dx$$ So in first integral, if I compare it with : $ \frac{1}{\sqrt x}$ I have: $$\lim_{x…
Laura
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Why $\boldsymbol{\int_{-\infty}^0 \frac{dx}{3-4x}}$ does not exist?

Can anyone explain why $\int_{-\infty}^0 \frac{dx}{3-4x}$ does not exist? I know this will get $$-0.25 \lim_{t\to -\infty}(\ln (3-0)-\ln(3-4t))$$ As I know $$\ln(3+((-4)(-\infty)))=\ln(3+\infty)=\infty$$
user32104
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Is the improper integral $\int^1_0f(x)\,dx$ convergent if $\lim\limits_{x\rightarrow 0}f(x)=L$?

Suppose $f$ is a function that is only discontinuous or undefined at $x=0$ if $\lim\limits_{x\rightarrow 0}f(x)$ exists is the improper integral $\int^1_0f(x)\,dx$ convergent? Also suppose $g$ is a function that is only discontinuous or undefined at…
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Divergent improper integral

I have to determine if the following integral converges/diverges. I know that the integral diverges, but I can't find a way to prove it. $\displaystyle\int_1^{+\infty}\frac{1-\cos(x)}{\left(\sqrt{1+x^2}-1\right)\arctan\left(\sqrt{x}\right)}\,\mathrm…
rik
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Asymptotic behavior of integral with sinc and exponential functions

I have an integral of the following formbehavior $$ \int_0^{\infty}\frac{dk}{2\pi^2}\frac{\sin kr}{kr}k^2\exp\left[ -\frac{1}{2}(k R)^n \right] $$ I need to determine the asymptotic behavior for the integral at large distance $s\equiv r/R\rightarrow…
Judas503
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Verify convergence of improper integral

Let $f: (0,\infty) \rightarrow \mathbb{R}$, where $f(x) = \int_{0}^{1} \frac{t^x-1}{\log{t}}dt$. I want to check if this improper integral is convergent or not (when $t>0$), and have tried out different measures, but couldn't find any thing that…
flo
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How to solve this integral? - A Proof is needed

I am trying to solve this integral $$\int_{0}^{\pi /2}\sin^n x\cdot dx.$$ I think we should solve it for: a) odd numbers $2n+1$ $$\int_0^{\pi /2}\sin^{2n+1}x\cdot dx = \int_0^{\pi /2}\sin x\cdot \sin^{2n}x\cdot dx=\int_0^{\pi /2}\sin x\cdot …
Anakin
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How do I approach showing that integral $\int^{\infty}_0\sin^3(x^2+2x)$ converges absolutely/conditionally?

How do I approach showing that integral $$\int^{\infty}_0\sin^3(x^2+2x)\,\mathrm dx$$ converges absolutely/conditionally? I have calculated via software that $\int^{\infty}_0\sin^3(x^2+2x)\,\mathrm dx$ is indeed convergent, but how is it done…
user895986