Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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How to generalize induction from this definition?

Definition: An inductive set $A$ is a one that satisfies: $1\in A$ and $k \in A\implies k+1\in A$. If we characterize the natural numbers as the set which has the following properties: $\Bbb N$ is inductive. If $H$ is inductive then $\Bbb N…
YoTengoUnLCD
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Induction proofing of a sequence

A sequence $a_n$ is defined by: $a_1=1, a_2 = 1, a_n = a_{n-1} +2*a_{n-2}$ for all n> 2. show that $a_n = 1/3*(-1)^{n-3}+{2^n}/3$ by induction. I'm not quite sure on how to approach this induction as I haven't really learnt it yet, but I think you…
Smithy
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Using induction more than once in a proof

Is it possible to use induction twice or more in a proof? For instance, say we wished to prove the following proposition by induction: Proposition Suppose $x>3$ and $y<2$. Then $x^2 -2y>5$ Scratch Work Let $P(x,y)$ be the inequality $x^2 -2y>5$.…
user261954
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Can I use induction by $|V|$ here?

Show that any connected, undirected graph $G = (V,E)$ satisfied $|E|≥|V|-1$. Can I use math induction by $n = |V|$ here (remove and add vertex)?
Simankov
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I have to prove by mathematical induction that $\frac{(2n)!}{n!(n+1) !}$ is a natural number for all $n\in\mathbb{N}$.

I have to prove by mathematical induction that $$\frac{(2n)!}{n!(n+1) !}$$ is a natural number for all $n\in\mathbb{N}$. Any help would be really awesome.
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Prove by induction that $\sum_{k=1}^{n} k^3 = \bigg( \sum_{k=1}^{n}k\bigg)^2$

Show the following for all positive integers using proof by induction: $$\sum_{k=1}^{n} k^3 = \bigg( \sum_{k=1}^{n}k\bigg)^2$$ Base case (n = 1) passes: $1^3 = 1^2$ We assume the following: $$\sum_{k=1}^{p} k^3 = \bigg(…
lawls
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Need Help Understanding Algabraic Steps in an Inductive Proof

This question is about an inductive proof which was posted yesterday on this web site here: https://math.stackexchange.com/questions/1371540/proving-frac5-cdot34n-1-22n7-is-an-integer. This topic was put on hold as off topic. I'm pretty rusty on…
Willard
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Proving that the sum of the first $2n$ terms of the series $1^2 - 3^2 + 5^2 - \cdots$ is $-8n^2$ by induction

Use mathematical induction to prove the following for the first $2n$ terms of the series $$1^2 - 3^2 + 5^2 - 7^2 + \cdots = -8n^2.$$ As we have odd numbers that are squared we could use $n = 2k-1$. But the $2$ sides do not equate for $n=1$ or…
J132
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INDUCTION: Let a sequence of numbers $a_n$ for $n\in \mathbb N$ be defined by the following rule: $a_1 = 1$, and for $n>1$, $a_n = 2a_{n-1} + 1$

Prove that $a_n = 2^n - 1$ for all $n\in\mathbb N$. I don't see how the sub n and n to the power of anything can correlate. I'm missing something for I've been staring at the combinations I tried to work out for a couple hours now ._.
Soap
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Proving binary integers

This is a very interesting word problem that I came across in an old textbook of mine. So I know its got something to do with binary integers (For ${0, 1, 2, 3}$ we have the representations $0, 1, 10, 11$), but other than that, the textbook gave no…
anonymous
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Proof by induction that $3^n - 1$ is an even number

How to demonstrate that $3^n - 1$ is an even number using the principle of induction? I tried taking that $3^k - 1$ is an even number and as a thesis I must demonstrate that $3^{k+1} - 1$ is an even number, but I can't make a logical argument. So…
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How to prove $\sum_{k=1}^{n}F_k = F_{n+2}-1$ by induction when $F_n$ is the Fibonacci sequence

Let $F_n$ be the Fibonacci sequence where $F_0$ = 0 , $F_1$ = 1 and $F_n$ = $F_{n-1}$ + $F_{n-2}$. I want to prove the following by induction. $$\sum_{k=1}^{n}F_k = F_{n+2}-1$$ Here is what I have so far. Can anybody tell me if…
User
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Can mathematical inductions work for other sets?

I know that induction works only for the natural numbers $\mathbb{N}$. We first have to prove the base case. And we then prove that if the statement $p(k)$ holds then $\color{blue}{\textbf{p(k+1)}}$ also holds. Now what if we want to prove a…
alkabary
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Prove by Induction - Sequence

The sequence $x_1, x_2, x_3, \ldots$ is such that $x_1 = 1 $ and $$x_{n+1} \space = \frac{1+4x_n}{5 + 2x_n}$$ Prove by induction that $x_n > 0.5$ for all $n \ge 1$. I have absolutely no clue how to go about this one. Can someone please explain. Very…
Ali Naqvi
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Prove ${4n \choose 2n} = {\frac{1\cdot3\cdot5\cdots(4n-1)}{(1\cdot3\cdot5\cdots(2n-1))^{2}}}{2n \choose n}$

Prove that prove $\dbinom{4n}{2n} = \dfrac{1\cdot3\cdot5\cdots(4n-1)}{(1\cdot3\cdot5\cdots(2n-1))^2} \dbinom{2n}{n}$ using mathematical induction. I have looked all over the internet, been able to prove a similar problem, but this one has me…
Ashley
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