Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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Prove using mathematical induction pt 2

Assumed that i asked a question like 30 min ago thinking i got the hang of this, seems not. So $$1^2+4^2+7^2+\dots+(3n-2)^2=\frac12n(6n^2-3n-1) \text{ for all } n\in\mathbb N$$ This time it seems way harder with the squares. so i did the steps and…
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Help with question about proving equality between recurrence and non recurrence equation.

I have this question, we have $a_1,a_2,a_3,\dots$ that is defined as $a_1=4,a_{n+1}=a^2_n-2$ for $n \geq 1$. Show that $y_n=(2+\sqrt{3})^{2^{n-1}}+(2-\sqrt{3})^{2^{n-1}}$ for all positive integers $n \geq 2$. I guess this is done by induction, but…
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Problem in understanding the mathematical induction

Suppose we have a subset of the set of natural numbers. This set includes 100 numbers that is the first 99 numbers is even and the last number is odd. now, induction can be said that the first number is even(first number mod 2 = 0) and number n +…
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Prove using mathematical induction that for every positive integer n, $\sum_{i=1}^n ( i * 2^i ) = (n-1) 2^{n+1} + 2 $

Prove using mathematical induction that for every positive integer n, $$\sum_{i=1}^ni2^i=(n-1) 2^{n+1} + 2$$ There is what i did so far :
timu
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Proof by induction that alternating sum of binomial coefficients is $0$

$\forall n \in \mathbb N :$ $A(n): \sum_{k=0}^n \binom{n}{k} \cdot(-1)^k = 0$ Initial step: $A(1): \binom{1}{0}\cdot(-1)^0 \binom{1}{1}\cdot(-1)^1 = 0$ $\iff 1 = 1$ $\iff 0 = 0$ The initial step turned out to be correct. Induction hypothesis:…
user105587
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Mathematical induction... divisible by 4

Hello I need to proof that the expression $(9^{n}+3)$ is divisible by $4$. It is true if I calculate it for $n=1$ for $n + 1$ I got stuck in here: $9 \cdot 9^n + 3$ I don't know how to continue. Can anyone help me please?
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Induction over negative number

Suppose I were given the task of proving that for all negative integers $3n^{2} \equiv 3n \pmod{6}$. The original intent was to use negative induction. But, I was wondering if another, perhaps simpler approach might be to exploit the fact that…
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Prove by induction that for all natural numbers, n, either 3|n or 3|n+1 or 3|n+2?

That is prove that for all natural numbers, n, either 3 is a factor of n or n+1 or n+2
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Showing "$30$ divides $n^5-n$ for all $n\in\Bbb N$" using induction

Prove that $(n^5 - n)$ divides by $30$ for every $ n\in N$, using induction only. How on earth do I do that? Thing is $(n^5 - n)$ can't be opened using any known formula...
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Help with Induction problem?

I'm not sure where to start on this induction problem. Problem: A group of $n \geq 1$ people can be divided into teams, each containing either 4 or 7 people. What are all possible values of $n$? Use induction to prove that your answer is…
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Induction proof that $n! > n^3$ for $n \ge 6$, and $\frac{(2n)!}{n! 2^n}$ is an integer for $n \ge 1$

Prove by induction that (a) $n! > n^3$ for every $n \ge 6$. (b) prove $\frac{(2n)!}{n!2^n}$ is an integer for every $n\geq 1$ I'm quite terrible with induction so any help would be appreciated.
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Induction with inequality problem

Prove by induction that $2k(k+1) + 1 < 2^{k+1} - 1$ for $ k > 4$. Can some one pls help me with this? I reformulated like this $ 2k(k+1) + 1 < 2^{k+1} - 1 $ $ 2k^2+2k+2<2^{k+1}$ and I tried like this Take $k=k+1$ $ 2^{k+2} -1 > 2(k+1)(k+2) + 1…
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Basic Mathematical Induction

I'm not quite sure how to approach this question. I need to prove that for $$n\ge1$$ $$1^2+2^2+3^3+\dots+n^2=\frac16n(n+1)(2n+1)$$ Do I just plug $1$ and see if $$\frac16(1)((1)+1)(2(1)+1) = 1^2\text{ ?}$$
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Prove by structural induction that L1 ⊆ L2

Consider the alphabet {a, b}. Also consider the following two languages: Let L1 be the smallest set such that Basis: The empty string A is in L1. Induction: For every x ∈ L1, both ax and axb are in L1. L2 = {ai bj|i ≥ j} Prove that L1 = L2…