Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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Show that by induction method that $2^{2^n}+1$ has $7$ in unit's place for all $n\geq 2$.

Show that by induction method that $2^{2^n}+1$ has $7$ in unit's place for all $n\geq 2$. I have tried to show this with the following way : Let $f(n)=2^{2^n}+1$. Then for $n=2,f(2)=2^{2^2}+1=17\Rightarrow f(2)\equiv 7(\mod 10) $ Suppose for…
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Inductive proof of $\sum_{i=0}^{n} 2^{-i} \binom{n}{i} = \left(\frac{3}{2} \right)^n$

I am trying to prove by induction on $n$ the following theorem: $$\sum_{i=0}^{n} 2^{-i} \binom{n}{i} = \left(\frac{3}{2} \right)^n$$ For my inductive step I have: $$\sum_{i=0}^{n+1} 2^{-i} \binom{n+1}{i}$$ $$\sum_{i=0}^{n} 2^{-i} \binom{n+1}{i} +…
jaynp
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Proof that $3 \mid 10^{n+2} - 2*10^n + 7, \forall n \in \mathbb{Z}^+$.

This is what I have so far. Proof by Induction. Let $n \in \mathbb{Z}^+$ Let $P(n)$ be the statement that $10^{n+2} - 2*10^n + 7$ is divisible by 3. ($\textit{Base Case}$): Let $n = 1$. $$ 10^{1+2} - 2*10^1 + 7 = 1000 - 20 + 7 = 987 $$ $3 \mid 987$…
Aidan
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Induction with inequalities

Im and quite new to induction and I don't know how use induction to prove inequalities such as $4^n>n^2$ and $2^n>n$ both for $n≥1$. For $2^n>n$ first I proved a base case 2>1. Then I substituted n for k then tried $k+1$. $2 \cdot 2^k>2k>k+1$ but…
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Proof by induction that $17n^3+103n$ is a multiple of 6

Problem use induction to prove that $17n^3+103n$ is a multiple of 6. Im new to learning proof by induction and was wondering if my proof would be acceptable for my maths test coming up. Proof. base case $n=1 = 120$ $17k^3+103k=6a$ for some $a$. then…
allan
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mathematical induction to prove $n=6x+13y$

Prove using Mathematical Induction (without strong MI) that any number n >=60 can be expressed as $6 *x + 13 *y$ where x and y are non-negative. My Thoughts: Let $n= 6*x+13*y$ then $n+1 = 6*(x-2) + 13 * (y+1)$ so it can be expressed but then there…
nicku
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Proving by induction by using a t = n+1

I figured that for any induction that I write down I can just use a t = n+1 and the entire question becomes as easy as doing 1+1. and obviously it cant be legal to do so, but I wonder why, can someone explain? example : Prove by induction that for…
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Proving polynomial division examples through Mathematical Induction

While proving the examples of polynomial division through mathematical induction, I am led to a curious conclusion, here is an overview: The following statement holds true for all whole number values of 'n'. $ \frac{x^n - y^n}{1} $ = p(x-y)…
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Use induction to show $(1+a)^n \ge na$ for $n\in \mathbb{N}$ and $a>0$.

I am familiar with Bernoulli's inequality which is quite straightforward to prove using induction, but this problem (although simpler at first glance) seems to be more complicated. What do you guys think? Please stop posting solutions on proving…
Matt
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How do I Prove (by induction) that the series $1^3+2^3+...+n^3=(1+2+...+n)^2$?

This is a question from my textbook, it goes like this: Prove (by induction) that the series $1^3+2^3+...+n^3=(1+2+...+n)^2$ Here is my attempt at a solution: The base case would be: $n = 1 \implies 1^3=1^2$ Then we suppose that the statement works…
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Can assume two statements in Induction step.

I was solving the following question a while ago: Let $\alpha$ and $\beta$ be the roots of $x^2 - 6x +1 = 0$. Show that $\alpha^n + \beta^n$ is an integer for any integer $n\ge0$ and it is not divisible by 5. I proved it with Mathematical…
VVR
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Understand how to prove by induction $\sum_{k=0}^n{{(-1)^k}{\binom nk}{k^m}}$

I want to understand how do you prove by induction: $\sum_{k=0}^n{{(-1)^k}{\binom nk}{k^m}}=0$ where $0 \leq m < n$. As far as I understood I have to: Prove the initial case $n = 1$ Assume the hypothesis $\sum_{k=0}^n{{(-1)^k}{\binom…
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Induction of inequality involving AP

Prove by induction that $$(a_{1}+a_{2}+\cdots+a_{n})\left(\frac{1}{a_{1}}+\frac{1}{a_{2}}+\cdots+\frac{1}{a_{n}}\right)\geq n^{2}$$ where $n$ is a positive integer and $a_1, a_2,\dots, a_n$ are real positive numbers Hence, show that…
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Show, by induction, that $T(n) = \frac{n(n+1)}{2}$ given the defined piecewise function.

I have no idea how to solve this. My math proving skills are pretty rusty. The problem gives the following definition to start: $$T(n) = \begin{cases} 1 \text{ if } n = 1 \\ T(n-1) + n \text{ otherwise} \end{cases}$$ Show, by induction, that…
amGz
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