Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

10150 questions
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Inequality with fraction

I have tried with some numbers and the following dependency is true. But I have no idea on how to prove it? Notice that, the maximal value of $\ell$ is $n$ and the values of $l$ can be $l=k+1, k+2, \ldots, n$. Thanks in advance! $$…
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Problem with a proof by induction

I'm trying to prove that $n^2+n+3$ is odd. I don't know how to figure out the solution because there isn't a formula.
gefavasej
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How can I prove that: $\frac{(n+1)(n+2)(n+3)...(3n)}{(1*2)(4*5)(7*8)...(3n-2)*(3n-1)} = 3^n$

How can I prove that: $$\frac{(n+1)(n+2)(n+3)...(3n)}{(1 * 2)(4*5)(7*8)...(3n-2)*(3n-1)} = 3^n$$ Can you help me and explain me how can I prove it? I thought to prove it by induction, but I don't have idea how to do it in fact.
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Using induction on $k$, show that $\sum\limits^{n-1}_{i=1} i^k \le \frac{n^{k+1}}{k+1} \le \sum\limits^n_{i=1} i^k$

Prove using induction on $k$ that $\sum^{n-1}_{i=1} i^k \le \frac{n^{k+1}}{k+1} \le \sum^{n}_{i=1} i^k$ I need to assume $\sum^{n-1}_{i=1} i^p \le \frac{n^{p+1}}{p+1} \le \sum^{n}_{i=1} i^p$ and prove that $\sum^{n-1}_{i=1} i^{p+1} \le…
Savannah
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Prove via induction $\sum_{k=2}^{n}{\frac{k-1}{k!}} = \frac{n!-1}{n!}, \forall n \in \mathbb{N}, n \ge 2$

I have to prove by induction, that $$\sum_{k=2}^{n}{\frac{k-1}{k!}} = \frac{n!-1}{n!}, \forall n \in \mathbb{N}, n \ge 2$$ $\begin{align} \sum_{k=2}^{n+1}{\frac{k-1}{k!}} &= \sum_{k=2}^{n}{\frac{k-1}{k!} + \frac{(n+1)-1}{(n+1)!}} \\ &=…
jublikon
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Prove that among any consecutive $2017$ lamps not more than $k/2$ lamps are on

Given a row of $10^6$ lamps, all of them are initially off. Each of $2016$ people approaches the row and switches any $2017$ consecutive lamps. (One turns on lamps which are off, and turns off lamps which are on). It turned out that at the result…
G. Amber
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Mathematical Induction ($2^n\ge n^4$ for $n\ge n_0$)

I'm trying to prove a statement with M.I. Here is my statement: There exist an $n_{0}\epsilon\mathbb{N}$ such that $2^{n}\geq n^{4}$ for all $n\geq n_{0}$ Well, when I start to prove: Initial step: Let n = $n_{0}$ I get $2^{n_0}\geq…
Tiro
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Can I rewrite part of this induction?

Let $f_0 = 1$, and $f_1 = 1$, and $f_n = f_{n-1}+f_{n-2}$ when $n \gt 1$ (the Fibonacci sequence) Prove using induction that $f_n\gt 2n$, when $n \geq 6$. (note the $f_6 = 13$, $f_7=21$) I want to rewrite $f_n \gt 2n$ as $f_n\gt f_{2n}$ is this…
lampShade
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Prove by induction with summation and factorials

Sorry I'm not sure how to format the text for using sum. Could someone help me out with that as well. Much appreciated. \begin{eqnarray*} \sum_{r=1}^{n} (r^2+1)r! =n(n+1)! \end{eqnarray*} for all $n \geq 1 $.
Thomas
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Show that if $S$ is a finite set with n elements, then $S$ has $2^n$ subsets by using mathematical induction

I don't understand this exercise of mathematical induction. I also have the answer but I still don't get it. The exercise says the following: Use mathematical induction to show that if $S$ is a finite set with n elements, then $S$ has $2^{n}$…
Arnau
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How do I prove that $1^4+2^4+3^4\cdots\ + n^4 = \frac{1}{5}n^5 + \frac{1}{2}n^4 + \frac{1}{3}n^3-\frac{1}{30}n$?

How do I prove that $1^4+2^4+3^4\cdots\ + n^4 = \frac{1}{5}n^5 + \frac{1}{2}n^4 + \frac{1}{3}n^3-\frac{1}{30}n$? I've spent quite some time on this problem. So far, I've simplified the right-hand side to $\frac{1}{30}(n+1)[(2n+3)(3n^3)+n(n-1)]$. But…
Skm
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There are three kinds of liquids X, Y , Z,. Three jars J1, J2, J3 contain 100 ml of liquids X, Y , Z, respectively. By an operation we mean...

Problem: There are three kinds of liquids X, Y , Z,. Three jars J1, J2, J3 contain 100 ml of liquids X, Y , Z, respectively. By an operation we mean three steps in the following order: stir the liquid in J1 and transfer 10 ml from J1 into J2 ; …
oshhh
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Given the recurrence $T_n = 5T_{n-1} - 6T_{n-2}$ ,Prove by induction $T_n = 3^n - 2^n$ is the solution.

Given : $ T_0 = 0 $ , $T_1 = 1$ Base case : $T_2 = 5T_1 - 6T_0 = 5 = 3^2 - 2^2$ $T_3 = 5T_2 - 6T_1 = 19 = 3^3 - 2^3$ Assumption : $T_n = 3^n - 2^n$ & $T_{n-1} = 3^{n-1} - 2^{n-1}$ To prove : $T_{n+1} = 3^{n+1} - 2^{n+1}$ $T_{n+1} =…
Johnathan
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Prove the following inequality by induction for all $n\in \Bbb N$

I know how to prove the base case for this. But how would I continue from there?
user483618
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Two questions with mathematical induction

First hello all, we have a lecture. It has 10 questions but I'm stuck with these two about 3 hours and I can't solve them. Any help would be appreciated. Question 1 Given that $T(1)=1$, and $T(n)=2T(\frac{n}{2})+1$, for $n$ a power of $2$, and …