Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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Prove this sum of binomial terms using induction.

Here's the problem stumping me today: Let $n \in \mathbb{N}$ and $r \in \mathbb{N}$ such that $r \leq n$, and prove using induction that $\binom{n+1}{r+1} = \sum\limits_{i=r}^n \binom{i}{r}$. I've setup the basics of my inductive proof, but I'm…
user176049
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Proof by induction steps

Today in class, the instructor is trying to show that for $n \ge 0$, $n < 2^n$. And this are the steps he took: First we assume the inductive hypothesis i.e. $0 < 2^0$, and this is true. Then to prove that for any arbitrary integer $k \ge 0$, $k <…
smac89
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Using strong/simple induction instead of structural induction.

Let S be the set of ordered pairs of integers defined recursively by $(0,0) \in S$ If $(a,b) \in S$, then both $(a+1, b+1) \in S$ and $(a+3,b) \in S$ And define the set $S'$ = {$(x,y) \in \mathbb{N} \times \mathbb{N}$ | $x \ge y$ and $ 3…
t3c
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Proof my by mathematical induction $\sum_{i=1}^{n} \frac{(-1)^{i-1}}{i} > 0 $

I proved it true for the base case but have no idea how to implement the assumption that it's true for n=k when trying to prove for n=k+1. Am i right in saying there would be two cases i.e. k is odd or even.
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Induction question?

I have a problem that is supposed to use induction, but I have no idea how to solve it. Could I get some help? The closed form sum of 12 $\left[ 1^2 \cdot 2 + 2^2 \cdot 3 + \ldots + n^2 (n+1) \right]$ for $n \geq 1$ is $n(n+1)(n+2)(an+b)$. Find an…
Bob Joe
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Solving a question by mathematical induction

Question : Prove that $$ \sum_{k=1}^n\frac{1}{\sqrt{k}}\le 2\sqrt{n}-1 $$ for all positive integers $n$. I've been thinking a solution for this question for hours but still can't solve it.
Paul
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Mathematical Induction

The sequence of real numbers $a_1$, $a_2$, $a_3$...is such that $a_1$ $=$ $1$ and $a_{n+1} = (a_n + \frac{1}{a_n} )^{\lambda}$ ,where $\lambda$ is a constant greater than 1. Prove by mathematical induction that for n ≥ 2, $a_n$ ≥ $2^{g(n)}$ where…
user140161
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prove by induction, not for natural numbers this time, but for real numbers

Prove by induction: suppose there's a vertical column, infinitely tall from the ground. from 0 inches to 2 inches are dangerous zone, and up from 2 inches are safe zone. If you care climbing this column, you can jump up 1 inch for every move, but…
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Proof By Induction that $3^{(2^n)} -1$ is divisible by $2^{(n+2)}$

How do I prove the $(n+1)$-th case for this equation?
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Can someone help me complete this easy proof by induction

$P(n): for -1 (1+x)^n >= (1+nx)$ $P(1): (1+x) >= (1+x)$ $P(n+1): (1+x)^{(n+1)} = (1+x)^n*(1+x) ....$ where to go from here?
Olórin
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Induction -- n to n+1

I'm trying to understand an induction proof that aims to prove some function is in $O(n\log{ n})$. It's on page 5 of this PDF: https://courses.engr.illinois.edu/cs573/fa2010/notes/99-recurrences.pdf The function is $$T(n)=\sqrt{n}\, T(\sqrt{n})…
student
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Induction, not what, but how it's done?

I have a simple formula for the n-th derivative of some expression. I'm suppose to prove that it's true for all N, by using induction. I set n=1, and show that the base case works. The next step, were I assume that it works a K is fine. But how is…
Algific
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Induction based proof.

Let S be an ordered set. Let $A \subset S$ be a nonempty finite subset. Prove that $A$ is bounded, that inf A exists and is in $A$, and that $\sup (A)$ exists and is in $A$. Hint: Use induction. (A finite set is a set from which, for some $n \in…
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Suppose that $n\geq 1$ .Use induction to prove that $(1 + a)^n \geq 1 + an$ for every $n$ element in $\mathbb{N}$.

I am having difficulty to finish my proof. Please help me finish and understand . Suppose that $a \geq -1$ .Use induction to prove that $(1+a)^n\geq1+an $ for every $ n\in$ N. Be sure to say where the assumption that $a\geq -1 $ is used. Proof: For…
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Rule or Formula to get from j^2 + 3j + 2 to (j + 1)(j + 2)

Apologies in advance if this problem is a duplicate. I'm not even sure how to properly research it. Studying algorithms (actually still in the prerequisite step of data structures) and an explanation of the Principal of Induction demonstrates…
MikeiLL
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