Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

10150 questions
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A problem on mathematical induction

This question I am feeling very difficult to solve. It is said to be a problem on mathematical induction: On a circular path, there are are $n$ cars and among them they have enough fuel to cover the entire circumference of the circular path. I…
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Induction, show that something is smaller then ...

I have to show the following by induction. $1 \cdot 2 \cdot 3 ... (n - 1) \leq (\frac{n}{2})^{n -1}$ As it is homework I "only" need a push in the right direction. my thought is that is something to do with the binomial theorem.. but I'm pretty…
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Induction when not dealing with Sigma notation

How do you prove $4^n > 3^n + 2^n$ using induction? Base case would be when $n = 2$, $16 > 13$. Then assume $n = k$ so that $4^k > 3^k + 2^k$. Then let $n = k + 1$ so that $4^{k+1} > 3^{k+1} + 2^{k+1}$ But then what? What am I trying to match up so…
Adam
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Prove that $\sum\limits_{k=0}^n\ 2\times3^{k-1} = 3^n-1$

Hope someone can enlighten me on how to show via induction that $\sum\limits_{k=0}^n\ 2\times3^{k-1} = 3^n-1$
z3po
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Show that this summation is an invariant of the loop in algorithm

I'm having trouble with induction with this specific problem. a) Show that $\sum_{i=0}^k 2^i = 2^{k+1} - 1$ is an invariant of the loop in algorithm begin k := 0 while 0 ≤ k do k := k + 1 end b) Can you use (a) to prove that summation for…
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Show that a number divides

How do I show that for all integers $n$, $n^3+(n+1)^3+(n+2)^3$ is a multiple of $9$? Do I use induction for showing this? If not what do I use and how? And is this question asking me to prove it or show it? How do I show it?
Adam
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Mathematical induction issue

I am struggling with two examples for my homework. I'd appreciate some help. I think the weak principle of MI is enough to solve them. Instructions are same. Prove that ... Assume that (0) step (prove for value 1) is true, I need step (1) (induction…
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Prove $(1 - a)^n \geq 1 - na$ for $0 < a < 1$

This is exercise problem from "The Art of Computer Programming - Fundamental Algorithm". Prove by induction that if $0 < a < 1$, then $(1 - a)^n \geq 1 - na$ Here is my attempt: If n = 1, then $1 - a \geq 1 - a$ is true. We may assume by…
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Proof by induction ${n\choose k }\le n^k$

Ok, so the question is to prove by induction that: $${n \choose k} \le n^k$$ Where $N$ and $k$ are integers, $k \le n$; How do I approach this? Do i choose a $n$ and a $k$ to form my base case?
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Induction with multiple variables

Let the function g : R $\rightarrow$ R satisfy $g(xy) = x \cdot g(y) +y \cdot g(x)$ for all real numbers x and y. Prove $g(u^n) = nu^{n-1}g(u)$, for all positive integers $n$ and all real numbers $u$. the Inductive step for me is a bit tricky, the…
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In a proof by induction, can one prove the inductive step by contradiction?

Proof by induction consists in following scheme: Proof by induction or intuitively, let be a predicate $ P(n) $ with $ n \in \Bbb{N} $: if $P(0) $ is true $P(k)\to P(k+1), \forall k \in \Bbb{N} $ is true then $P(n), \forall n \in \Bbb{N}$ is…
mle
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Prove that $n! > 2^n$ for $n\geq 4$ (solution question)

I'm having a hard time figuring out a part of the solution So I'm trying to prove $n! > 2^n$ for $n \geq 4$ and the solution is attached as a picture I'm confused as to what happens from the solution line 2 to 3. I don't get the "since k >= 4 and…
Jack
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solve by induction

$$\sum_{r=2}^n{1\over r^2-1}=\frac34-{2n+1\over 2n(n+1)}$$ after I got to $n=k+1$ and tried to get both sides equal I got stuck, prove: $n=k+1$ ; $${1\over k^2 -1} + {1\over (k+1)^2 -1}=\frac34 - {2(k+1) +1\over 2(k+1)(k+2)}$$ any help would be…
luke
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Show that $2^n < n!$ for every positive integer $n$ with $n\geq 4$.

Using Mathematical induction prove the above proposition. Basis step can be verified easily. But how can i show that it is true for $p(n+1)$.
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Induction: show that $\sum\limits_{k=1}^n \frac{k}{2^k} = 2 - \frac{n+2}{2^n}$ for all n $\in Z_+$

So the question in my textbook is: Show by induction that $\sum\limits_{k=1}^n \frac{k}{2^k} = 2 - \frac{n+2}{2^n}$ for all $n$ $\in Z_+$. My attempt at a solution: First of all $Z_+ = 1, 2, 3, 4, 5, 6, 7, 8 ...$ So I start to make sure that the…