Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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proof by induction: off by a factor of 3

I put something into wolfram alpha and I saw that it simplified really well. I wanted to try and prove it, but my attempt is leaving me short a 3. Where am I going wrong? $\sum_{i=0}^{m-1} 3^{m-1-i}2^{i} = 3^m - 2^m$ Base case: m = 1 $\sum_{i=0}^{0}…
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Proving that Number of Steps to Return to the Origin is an Even Number

I was watching the following video on Random Walks: https://www.youtube.com/watch?v=iH2kATv49rc Here, the following point is discussed: Suppose you have an infinite square grid. In each "step", you can move one "step" in the Up, Down, Left or Right…
stats_noob
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How does the $10^{j+1}-1$ to $10^{j}-1+9\cdot10^j$ conversion work?

We have an assumption $9|10^j-1$ and $j\in\mathbb{N}$ (inductive assumption) At this point the transformation occurs: $10^{j+1}-1=10^j\cdot10-1=10^{j}-1+9\cdot10^j$ from where we know: $9|10^{j+1}-1$ I would like to ask you to explain how we pass…
urshuk
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Mathematical Induction problem

Can somebody help me with these questions? I can't seem to get started... Having $P(n) : n^2 + 5n + 1\text{ is even}$. a) Demonstrate that if $P(k)$ is True to some $k$ natural, then $P(k + 1)$ is also true. b) Considering the Principle of Complete…
Vika
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help on: $f_{n+1}<(\frac{7}{4})^{n}, n\geq 1$

Just wanted to ask if someone could help me with this proof: $f_{n+1}<(\frac{7}{4})^{n}, n\geq 1$, where $f_{n+1} = f_{n}+f_{n-1}.$ The base case where $n=1$ is straightforward. I wrote down an induction hypothesis: $f_{k+1}<(\frac{7}{4})^{k},$ for…
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Prove using induction the claim is true

Jack has n amount of cards. At first, all cards are either green or red. However, Jack wants to transform all cards into black. He can only color the green card black. Additionally, when a card turns black, the adjacent card will turn red if they…
nnn
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Induction $n! - n^4 \ge n^2 - 11n\,$ for $\,n \ge \text{some } n_0$.

Task is to show that There exists some $n_{0} \in \mathbb N $, $\forall n \in \mathbb N $ $ (n_{0} \ge n \Rightarrow n! - n^4 \ge n^2 - 11n)$ Where to start with this? By Induction over $n$, assuming $n_{0} =1:$ Holds for $n_{0} =1:$ Assume $ k! -…
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simplest example of weak induction with vacuously true base case

I am struggling with the concept of vacuously true base cases in weak induction. Question - I would appreciate if readers provides simple examples of induction which use a vacuously true base case. My hope is that simple examples will help me focus…
Penelope
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Prove by mathematical induction that $\frac{n^3}{n!} < \frac{1}{2^n}$ for some $n\geq m$ where $m > 0$

Prove by mathematical induction that $\frac{n^3}{n!} < \frac{1}{2^n}$ for some $n\geq m$ where $m > 0$ To start off, I assume the hypothesis that it is true for $n$. Trying to prove for $n+1$, $$\frac{1}{2^{n+1}} - \frac{(n+1)^3}{(n+1)!} >…
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Using induction to prove statements for finite sets

As we all know, induction is used to prove statements concerning natural numbers. When we are making a proof by induction, we use the principle of mathematical induction or some variant of it. To my understanding, one of the principles we rely on…
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Seeking the analytical proof using the method of induction

Experimentally (using Wolframalpha) I noticed that for $n=2,3,4,5$ $\log[n^2] - \log[n^2 - 1] = \sum((\frac{1}{n^4})^{k+1}\left(\frac {n^2}{(2k+1)}+\frac {1}{2k+2}\right),k = 0\cdots \infty$ Wolframalpha also confirms the generalization of the above…
Alex
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Proof by Induction for an Inequality

In Tom Apostol's Calculus Vol 1, there is an exercise (i4.10 13) to prove by induction: $$\sum_{k=1}^{n-1} k^p \lt \frac{n^{p+1}}{p+1} \lt \sum_{k=1}^{n} k^p$$ It is a 3 part exercise, and in a preceding part, it says Let p and n denote positive…
shafe
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Induction strategy with mathematical symbols

The induction principle is used to prove a sequence of propositions $P_0, P_1, P_2, P_3, ...$. And it proceeds as follows (i) Verify $P_0$. (ii) Assuming truth of $P_k$ for some $k$, verify $P_{k+1}$. In this way, denoting by $S$ the set of those…
Veak
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Proof by induction confusion

When we do proof by induction our inductive step is to assume that the statement $P(n)$ holds for $n=k$, we then show that $P(k) \implies P(k+1)$, which my textbook writes as "If its true for $n=k$, show its true for $n=k+1$", now I would like to…
Nav Bhatthal
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Finding the formula for a series

Let $n\geq1$. Find a formula for the sum: $$S_n=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\cdots+\frac{1}{n\cdot(n+1)}$$ The formula for the sum should be based on n components of the last term: $$S_n= n\cdot\frac{1}{n(n+1)}$$ So that…
Luthier415Hz
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