Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

10150 questions
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Statement true for all prime numbers -- can this be done by Math Induction?

Let's say that you want to prove a statement is true for all prime numbers. Can this be done by Math Induction?
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Simple proof by induction problems

I just started learning proof by induction and I have come across 2 problems that I am not sure if am doing right. The first one is Prove that $11^n - 1$ is dividable by $10$. I started with $ n = 0, 11^0 - 1 = 0 $, is dividable by…
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Prove using mathematical induction that for all $n! \ge 2^{n-1}$

Prove using mathematical induction that for all $n! \ge 2^{n-1}$ Base case, p(1), 1! >= 1 $p(n+1), n!(n+1) \ge 2^{n-1}(n+1) $
day
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Math Induction proof union and intersections

I'm totally new to Math Induction. I have a question on using Math Induction proof with union and intersections. Here's the initial problem: Prove that, for if C, D1, D2, …, Dn are n + 1 sets, that $$C\bigcap(\bigcup_{i=1}^nD_i)=\bigcup_{i=1}^n(C…
Cathy Fenn
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Prove that $\sum_{i=0}^{n-1} {2^i} = 2^n -1$

I need to prove that $$\sum_{i=0}^{n-1} {2^i} = 2^n -1.$$ I tried induction but something didn't work.
Nir
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Induction problem clarification

here's the problem I'm doing: Prove that for all integers $n$ with $n \geq 1$, we have $n \cdot 6^n \leq (n+10)!$ I don't understand how to get from [$6 \cdot (k + 10)! + 6^{k+1}$] to $k \cdot (k + 10)! + 11 \cdot (k + 10)! $. Base Case: Let $ n =…
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Let $P(n)$ be a statement and let $P(n) \rightarrow P(n+1)$ is true for natural numbers n, the $P(n)$ is true for

a) For all $n$ b) For all $n>1$ c) For all $n>m$, $m$ being a fixed integer d) Nothing can be said We can assume that $P(n+1)=P(n)$ If we substitute $P(n-1)$, $$P(n) = P(n-1)$$ $$\implies P(n-1) = P(n+1)$$ What does this result mean? How is…
Aditya
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What is the correct statement for $n\in N$

There were multiple options for this question, but ultimately I am problems with just two of those ie. $n^4<10^n$ $2^{3n} >7n+1$ Now following the basic induction process, for the first option I got $$k^4…
Aditya
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Need help proving $1+3+\cdots+(2n-1)+(2n+1)+(2n-1)+\cdots+3+1=n^2+(n+1)^2$

I am having trouble in identifying how $n=k+1$ differs from $n=k$. Assume it is true for some integer $k \ge 1$, that is $1+3+(2k-1)+(2k+1)+(2k-1)+3+1$. I need help getting to how $n=k$ implies $n=k+1$ in this case.
Adam6
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Need help with mathematical induction

Suppose $a, b$ are positive real numbers. Then $\frac{a^n + b^n}{2} \ge \left(\frac{a+b}{2}\right)^n$ for any $n$ ∈ $\mathbb{N}$ \ {$0$}. How should I prove the above statement by mathematical induction? I am stuck in the step in proving $P(k+1)$.
Nat
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Prove that $n(T) = (2l(T) – 1)$ for all full binary trees T, using structural induction

I am wokring with proof by structural induction, and I'm not sure if I have solved the task correctly so far, I am also stuck at the last part of my proof. The number of nodes in a full binary tree, written n(T), defined recursively: $$n(T) =…
Mampenda
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Use induction to show that: $\frac{1}{2!} + \frac{2}{3!} + \frac{3}{4!} +\ldots + \frac{n}{(n+1)!} = 1-\frac{1}{(n+1)!}$

So far I have: Let $S =\left \{n \in \mathbb{N} \; \left |\;\frac{1}{2!} + \frac{2}{3!} + \frac{3}{4!} +\ldots + \frac{n}{(n+1)!} = 1-\frac{1}{(n+1)!} \right .\right \}$. Since $\frac{1}{2!} = \frac{1}{2}$ and $1- \frac{1}{(n+1)!} = \frac{1}{2},\; 1…
tt2019
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why does $4n-1$ specifies index of a set?

Hi I'm following a course on mathematical induction, and I found something that doesn't quite make sense to me The professor gave os this statement: $$3+7+11+\cdots+(4n-1) = n(2n+1)$$ then he goes straight on to test this with $n=1$, and goes…
s3j80
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Using strong mathematical induction to prove a statement

So I have a question that I got stuck on, it says I have to prove that all integers greater than 17 can be written using a sum of 7's and 4's. For instance 7 + 7 + 7 + 4 + 4 = 29 or 7 + 4 + 4 + 4 = 19 .... etc. Appreciate the help. Cheers.
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Question need to get a conjecture and prove by induction

The question is: Divide the plane into separate regions using $N$ lines according to the following rules: No two lines are parallel. No three lines intersect at the same point. When $N = 1$, the plane is divided into 2 regions. When two lines are…