Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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Mathematical induction inequality: $\sum_{r=1}^n\frac{1}{\sqrt r}>\sqrt n,~n\geq 2$

I am trying to solve the following problem with mathematical induction but I can't quite seem to work it out. Prove by mathematical induction that $$\sum_{r=1}^{n}{r^{-\frac12}}>n^{\frac 12}, \forall n\in \Bbb Z, n\ge 2$$
Steam
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Proof of factor by induction

Prove by mathematical induction that $4$ is a factor of $9^n - 5^n\,\forall n\geq1$. Please have a look at my attempt if it is correct or not.
uniBoi
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How to subset proof

I don't understand how to prove subsets of a universe by induction. I have only just started learning sets. Let B, C be subsets of a universe U. Prove that C' - B' = B - C Thank you, any examples would be highly appreciated.
Layken
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Inductive proof with $2 k$ instead of $k+1$

Is it valid to perform an induction proof using $2 k$ as opposed to using $k + 1$ in your inductive step? I tried searching but all I saw is that induction is done using $k + 1$.
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Is mathematical induction is about proving the expression or its validity over set of value assuming expression is correct.

Is mathematical induction is about proving the expression or is it about proving that expression is valid over a set of value(natural number), assuming expression is correct?
qwerk
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Removing constants in mathematical induction?

For which positive integer n is $21n +127 \leq 3^n$? Base case: \begin{gather} n=5\\ 21(5) + 127 \leq 3^5 = 243\\ 232 \leq 243 \end{gather} Inductive steps: \begin{gather} P(n+1) = 21(n+1) + 127 \leq 3^{n+1}\\\\ \text{Using the original base…
Carrein
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induction to m | $n,m \in \mathbb{N} $

$ n,m \in \mathbb{N} $. proof with induction to $m$: $$\binom{n}{n} + \binom{n+1}{n} + \binom{n+2}{n} + ... + \binom{n+m}{n} = \binom{n+m+1}{n+1}$$ Try to use: for $k < n$ its $$\binom{n+1}{k+1} = \binom{n+1}{k} + \binom{n}{k}$$ Now i have to do the…
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For every $n\ge3$ there exists $n$ different integers $a_1,...,a_n$ so that $\frac{1}{a_1}+\frac{1}{a_2}+...+\frac{1}{a_n}=1$

I have a hard induction problem here that I feel completly lost on. For every $n\ge3$ there is n different positive integer $a_1,...,a_n$ so that $\frac{1}{a_1}+\frac{1}{a_2}+...+\frac{1}{a_n}=1$. There is only one possible solution for $n=3…
Mevve
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Use the mathematical Induction show that $H_{2^n}\le n+1$

Use the mathematical Induction show that $H_{2^n}\le n+1$ here $H$ is harmonic numbers ie. $H_n=1+\frac{1}{2}+\frac{1}{3}+.....\frac{1}{2^n}$ my idea so for $n=0$ L.H.S=R.H.S Suppose this is true for $n$ we prove for $n+1$ So…
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how could we know that a theorem is suitable for proof by induction?

Theorems like (factorization theorem) aren't suitable to be proven with induction since induction requires that the property tackled with our set of variables must be satisfied consecutively; (prime numbers aren't consecutive). So, how could we be…
user316849
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Prove by induction $4$ is a divisor of $(3^n +2n-1)\; ,n\ge1$

Prove by induction $4$ is a divisor of $(3^n +2n-1)\; ,n\ge1$ My idea: for $n=1$ ,$3^n+2n-1=4$ therefor true for $n=1$ now suppose this is true for $n=k$ i.e,. $4$ is the divisor of $3^k+2k-1$ we have to prove for $n=k+1$ so consider $…
user546987
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Proving a sequence by induction

Trying to prove by induction in a non-math course and I feel like I'm getting the steps but I'm just stuck on the math. $$G_1 = 1$$ $$G_2 = 1$$ $$G_n = 2G_{n−1} + 3G_{n−2}, \quad n \geq 3$$ Using mathematical induction, prove that for every $n ≥…
B. Mars
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Solving an inequality induction

For all: $$ n \ge 6, 4n^2+1 < 3*2^n $$ p(n): $ 4n^2+1 < 3*2^n $ My work: Basis Step: P(6) 145 < 192 is true Induction Step: Let $ n\ge 6 $, Assume $ 4(n+1)^2 +1 < 3*2^{n+1}$ What should I do next??
Secret
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Induction $24|n^{6}-3n^{5}+6n^{4}-7n^{3}+5n^{2}-2n$

How to resolve this problem with induction? $24|n^{6}-3n^{5}+6n^{4}-7n^{3}+5n^{2}-2n$ Is there some way to make induction step without use of Binomial formula and all that calculating?
Ana
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Prove that every natural number >1 has a unique way of prime factorization

I am trying to prove that every natural number >1 has exactly one way of factorization by prime numbers. I read the wikipedia page but it is not so clear to me (they use strong induction). is there any other way to prove it ? maybe not by…