Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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Factorisation of Multiples of Algebraic Powers

Assume $f(k)$ $=$ $8^k$ $-$ $3^k$ is divisible by 5 I'm trying to prove $f(k+1)$ is divisible by 5. If I use $f(k+1) - f(k)$, and then add $f(k)$ to both sides, I get $f(k+1) = f(k) + 5(8^k)$ which is divisible by 5. However, I wan't to directly…
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Proof of a general statement

I was doing some proof by induction and I stumbled upon this general statement that I can't derive to save my life: $$\frac{k(k+1)}{2} + (k+1) = \frac{(k+1)(k+2)}{2}$$ Could you prove why it is true (don't verify it please I've already done that)
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Prove by induction that $n^3 \leq 3^n$ for all integers $\geq 3$

I have done easier induction proofs but I got stuck on this one. I start with checking the base case: $$3^3 \leq 3^3$$ $$27 \leq 27$$ So the base case holds. Next I assume it works for $p+1$ and want to prove it for $p + 1$ and this is where I get…
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Is this proof of "binomial coefficients are always natural numbers" correct?

I'm a high school graduate, who has started doing Spivak's Calculus, for fun. I was struggling a bit with a certain question on proving the above stated fact using Principle of Mathematic Indutction. I came up with the following proof, but am unsure…
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Proof by induction, inequality

The sequence of real numbers $\ a_1,a_2,a_3.....$ is such that $\ a_1=1$ and $$a_{n+1} = \left(a_n+\frac{1}{a_n}\right)^{\!\lambda} $$ where $\ \lambda >1$ Prove by mathematical induction that for $n\geq 2$ $$a_n\geq2^{g(n)} $$ where $g(n) =…
mathnoob123
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Induction showing max number of inversions to sort a list

Say you have a list and you can invert initial segments of the list. You can get from 3-4-2-1-5 to 4-3-2-1-5 (invert the first two) and then to 1-2-3-4-5 (by inverting the first two). Prove using induction that every sequence for n>=2 can be sorted…
Gabe
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Prove this equality using induction

I have problems proving this equality: $$1+\frac{n}{1!}+\frac{n*(n-1)}{2!}+\frac{n*(n-1)*(n-2)}{3!}+...+\frac{n*(n-1)...3*2}{(n-1)!}+\frac{n!}{n!}=2^n$$ Tried various options in inductive step of separating each addends that didn't help much. EDIT:…
domdrag
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Induction question for $\mathbb{Z}$

If you want to do induction on a parameter $a \in \mathbb{Z}$. In the base case, you prove it for $a=0$. And then you suppose it is true for $n$ and prove it for $n+1$ and $n-1$? Is that correct? Or you have to do induction for all $a\geq 0$ and…
bob
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Mathematical Induction Proof.

Prove that the following statement is true; $$8+11+14+...+(3n+5)= \frac12n(3n+13)$$So far I have P(1) is true. Assuming that P(k) is true; $$8+11+14+...+(3k+5)= \frac12k(3k+13)$$ Then I need to deduce that P(k+1) is true so,…
S17
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Lost on an induction proof my colleague called basic.

I just have no idear what is being asked (like what is set J) and if it is so basic why is it so general (I'm probably an idiot) . Prove by induction on n that for any finite set I with cardinality n with $\forall i \in I$ and $\forall a_i \in…
MaQ
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Prove the following: For all $k\in\mathbb{N},4^k>k$.

I will prove by induction the statement $P(k)$: "For all $k\in\mathbb{N},4^k>k$." The base case $P(1)$ results in $4>1$ which is a true statement. Thus, I assume $P(n)$ to be true and consider $P(n+1)$. $$4^{n+1} = 4^n \cdot 4 > 4n$$ I know that I…
jmoore00
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Mathematical Induction - Fractional Inequality

I don't mean to ask without show of any working, but I would like to have some hints, I've tried dividing both sides by (1+h), however, it lead me nowhere. Any hints as to how I should approach this question?
user51515
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Let S be a set inductively defined as follows

Let $S$ be a set inductively defined as follows: $2$ belongs to $S$, and if $x$ belongs to $S$ and $y$ belongs to $S$ then $xy$ belongs to $S$. A/ $S = \{2n \,|\, n \text{ belongs to } \mathbb{N}\}$ B/ $S = \{2(n+1) \,|\, n \text{ belongs to }…
pkim
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Proof by Induction of an inequality with a sum

Prove using induction on k that for any natural number 'n' $$\sum_{i=1}^n i^k \le \frac{n^k(n+1)}{2}$$ I know I first need to start off with a base case, which I think will be $k=0$ $$\sum_{i=1}^n i^0 \le \frac{n^0(n+1)}{2}$$ But I'm not quite sure…
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Proof by Induction: Help?

Prove by induction that $\displaystyle \sum_{i=0}^{n} (3\cdot 5^i) = {3(5^{n+1}-1) \over 4}$ for all non-negative integers, $n$. After induction hypothesis my equation becomes ${3(5^{k+1}-1) \over 4} + (3\cdot 5^{k+1}) = {3(5^{k+2}-1) \over…