Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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Prove by induction that there are infinitely many rational numbers between two distinct rational numbers.

I need to prove by induction that if $x, y \in\mathbb{Q}$ with $x < y$, then there is an infinite increasing sequence $\{z_n\}_n$ in $\mathbb{Q}$ such that $x < z_1 < z_2 < \dots < z_n < \dots < y$. I have tried to use $a_n = x + \frac{y-x}{2^n}$…
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Solving question using induction as a previous part

Prove (for example by induction on n) that $2^{mn} −1$ is an integer multiple of $2^m −1$, where $m,n \in \mathbb{N}$ Explain why this implies that $2^N −1$ for $N\in \mathbb N$ can only be prime if $N$ is prime. I have already proved by induction…
Jay
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Prove $\frac{k^7}7+\frac{k^5}5+\frac{2k^3}3-\frac k{105}$ is a integer by mathematical induction

This is what I got: If this must be possible i.e.if it must be an integer then $(\frac{15k^7}{7} + \frac{21k^3}{3}+ \frac{70k^2}{2}-k)$ must be divisible by 105. $k(\frac{15k^6}{7} + \frac{21k^2}{3} + \frac{70k}{2}-1)$ must be divisible by 105. For…
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question about part of one inductive proof exercise.

$$3+3 \cdot 5+3 \cdot 5^2+ \cdots +3 \cdot 5^n =\frac{3 \cdot (5^{n+1} -1)}{4}$$ basic step: n=1 $\quad 3+3 \cdot 5 = 3 \cdot (5^{1+1} -1)/4 \iff 18=18 \;$,  true assume: $\quad3+3\cdot 5+3\cdot 5^2+...3\cdot 5^k =3\cdot (5^{k+1}…
Deloss
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why Induction is Admissible?

This question has been always intrigued me. Why proof by Induction is admissible/acceptable ? We use this type of proof nearly every where and some times It's the easiest way of proof.
Itay.V
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Find the flaw in the proof

Find the error in the proof. This is the question: Theorem: Every positive integer is equal to the next largest positive integer. Proof: Let $P(n)$ be the proposition that $n=n+1$.To show that $P(k)$ implies $P(k+1)$, assume $P(k)$ is true such that…
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Induction of infinite series

A bit confused by this problem. Let {an} be the sequence defined recursively by a0 = 0 an+1 = square root of (2+an) a) Show that if an < 2 , then an+1 < 2. Conclude by induction that an<2 for all n. I'm pretty sure I got this part, I just…
Idiot
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How to prove $\frac{1}{1}+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2^n}≥1+\frac{n}{2}$

Okay, I definitely have to use induction I proved for the base case when $n=1$ and it was easy, but how do I prove when $n=k+1$?
George S
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Solve by induction, $(x+1)^2+(x+2)^2...(2x)^2$.

To prove: $$(x+1)^2+(x+2)^2...(2x)^2=(x(2x+1)(7x+1))/6$$ I got to the proving part using $P(K+1)$ which comes out to be $(x(2x+1)(7x+1))/6 - (x+1)^2 + (2x+2)^2$ not sure if my logic is right, what should i do after this? i tried to distribute and…
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how to find every n>2 where 8 + 5^(n-3) + 3^(n-3) that are divisible by 8 (using induction)

I need to find all natural numbers bigger then 2 where 8 + 5^(n-3) + 3^(n-3) is divisible by 8 I have already proven that it is true for all the even numbers. Now I know that it is false for odd ones, but i don't know how to prove it. n ≥ 3; n ∈…
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List of usefull calculation rules when performing an induction proof.

I have recently gone into studying induction. I am having trouble in general performing such a proof and it is not so much that i dont understand what the induction is about but more the problem that I get the feeling that I don't posses the tools…
Nulle
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Recursions and induction

If $a(n)$ is defined by: $$a(0)=1 \quad a(1)=3\quad a(2)=9 $$ and, for $n≥3$: $$a(n)=a(n-1)+2a(n-2)+5a(n-3)$$ show: $a(n) ≤ 3^n$ So I know that I'll have to use either Induction or Strong Induction to prove this statement. I'd begin by proving…
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Rationale behind mathematical induction

My apologies, I couldn't find a proper title for this question, if you do after reading question please edit it. I read about mathematical induction theory but still I don't see how is it useful? Can anyone please list me some trivial practical…
Mr.Anubis
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Proving that a function is a polynomial for any index n

I have the following information: For all $x \in \mathbb{R}$: $$T_0(x) := 1$$ $$T_1(x) := x$$ $$\forall n\in\mathbb{N}: T_{n+1}(x):= 2xT_n(x) - T_{n-1}(x)$$ Now I have to prove that for any $n\in\mathbb{N}$ The function $x\rightarrow T_n(x)$ is a…
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Why do we assume in the Principle of Strong/Complete Induction?

I get induction. (i) show that the statement holds when n=1 (or some basis) (ii) show that the statement holds for a general subsequent case, $n+1$. By PMI the statement holds for all cases. Dominoes, and all that. I get it. It makes sense. But when…