Questions tagged [logarithms]

Questions related to real and complex logarithms.

The logarithm is generally defined to be an inverse function for the exponential. If $x > 0$ is a real number and $b > 0$, $b \ne 1$, then the base-$b$ logarithm is defined by

$$\log_b(x) = y \iff b^y = x$$

The most commonly used bases are base $10$ and $2$ (which frequently arises in computer science), and particularly base $e$. The natural logarithm $\ln$ is defined to be $\log_e$.

Alternatively, the natural logarithm can be defined to be a primitive of the function $$f(t) = \frac{1}{t}$$ subject to the condition that $\ln{1} = 0$.

In the study of complex numbers, the solutions $a$ of $e^{a} = z$ are called complex logarithms. This uniquely specifies the modulus of $a$, but not its argument; as such, we define the principal logarithm $\operatorname{Log}(re^{i\theta}) = \ln{r} + i \theta$, with the restriction $-\pi < \theta \le \pi$ (or alternatively, $0 \le \theta < 2\pi$). This leads to a branch cut, or discontinuity - alternatively, the complex logarithm can be viewed as a multi-valued function.

Reference: Logarithm.

This tag often goes along with .

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How to solve for negative numbers in logarithmic equations

I am trying to solve the equation $$z^n = 1.$$ Taking $\log$ on both sides I get $n\log(z) = \log(1) = 0$. $\implies$ $n = 0$ or $\log(z) = 0$ $\implies$ $n = 0$ or $z = 1$. But I clearly missed out $(-1)^{\text{even numbers}}$ which is equal to…
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Number of digits in $12^{300}$

Given: $\log_{10}2= 0.3010$ and $\log_{10}3=0.4771 $, find the numer of digits in $12^{300}$ Options: $324,323,325,\text{Other}$ Actually I tried breaking 12 into 2*2*4.. And then tried to guess the series in no of digits increasing per…
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How to solve this logarithm equation

$$\log_2\left\{\log_3\left[\log_4\left(x^{3x}\right)\right]\right\} = 0$$ How would I go about solving this? I tried doing $\log_4(x^{3x}))=0$ but I don't know how to incorporate the other logs
Anny
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problem solving logarithmic equation and reaching an equivalence

ok so i've had a problem trying to simplify the $\ln\left[ \sqrt{1+\frac{u^2}{a^2}} + \frac{u}{a} \right]$ and this is supposed to be equal to : $\ln [ \sqrt{a^2+u^2} + u ]$ how is this posible ?? i've tried to solve this for more than 2 hours and…
shep
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Why does $\sqrt{x-x^{\frac{1}{x}^{\frac{1}{x}}}}=\log_{\sqrt{x-x^{\frac{1}{x}^{\frac{1}{x}}}}}(x)?$ (Error)

I might be being very silly here, but I can't for the life of me see why $$\sqrt{x-x^{\frac{1}{x}^{\frac{1}{x}}}}=\log_{\sqrt{x-x^{\frac{1}{x}^{\frac{1}{x}}}}}(x)$$for $x\in \mathbb{Z}, x>1$? $\left(\text{ie, }\log\text{ to the base…
martin
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How does $\left(\log \sqrt x\right)^2 = \frac 14(\log x)^2\;?$

So as the title says it all: How does $\;\left(\log \sqrt x\right)^2 = \frac 14(\log x)^2 \;?$ To be specific, why the removal of root, and how do we get 4 in denominator?
Swetank
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Find $z$ as a function of $w$ in terms of the complex logarithm, where $w=f(z):=2e^z+e^{2z}$

I have solved the following problem but would like to double check that I did it properly. The problem says: Find an expression for $z$ as a function of $w$ in terms of the complex logarithm, where $w=f(z):=2e^z+e^{2z}$, and use it to find all…
s1047857
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Solve $5^{2x+2}-5^{x+2}+6=0 $

How do we solve $5^{2x+2}-5^{x+2}+6=0 $? I know I have to use logarithms but I am not sure how to do it.
Issy
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I have issue in calculating log values

How is $$log_42= \frac{1}{2}$$ ? Any formula to how we calculate this? I know i am confused when base is larger digit than log value term.
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How to solve this logarithmic equation: $8n^2 = 64n\log_{\ 2}(n)$?

I want to solve this equation: $$8n^2 = 64n\log_{\ 2}(n)$$ After some steps, I get to a point in which I believe, the only way to proceed is to apply something like Bolzano's or Newton's method to find a solution. I get to: $n = 8\log_{\ 2}(n)$ Of…
Ruben
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How to interpret the difference in log points

How can we interpret the difference between two log points? Is it correct to interpret this difference in percentage points? Thanks. Marko
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Obtain the set of real numbers $c$

Show that there exists a positive real number $x \ne 2$ such that $\log_2 x ={x\over2}$ . Hence obtain the set of real numbers $c$ such that $\log_2 x\over x $$= c$ has only one real solution.
Ruddie
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Logarithm question-I donot know but this question may be solved by any other way also.

Let $(x_0,y_0)$ be the solution of the following equations. $$(2x)^{\ln{2}}=(3y)^{\ln{3}}$$ $$3^{\ln{x}}=2^{\ln{y}}$$ Then $x_0$ is A) $\frac{1}{6}$ B) $\frac{1}{3}$ C) $\frac{1}{2}$ D) $6$ I have tried this problem by taking log on both sides of…
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Logarithm Evaluating

i'm new to this site and I need help on this logarithm question. I don't know how to approach this question to simplify it. $\frac{\log _2\left(81\right)}{2-\log _2\left(18\right)}$ Apparently the answer is $-\frac{4\ln \left(3\right)}{\ln…
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Logarithmic problem with 2 variables help

How on earth do I solve? Any help will be much appreciated. The value of $M$ is given by $M = a \log_{10}S + b$. Note: Seismic moment measure the energy of the earthquake. Using the following information, determine the values of $a$ and…
steve
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