Questions tagged [logarithms]

Questions related to real and complex logarithms.

The logarithm is generally defined to be an inverse function for the exponential. If $x > 0$ is a real number and $b > 0$, $b \ne 1$, then the base-$b$ logarithm is defined by

$$\log_b(x) = y \iff b^y = x$$

The most commonly used bases are base $10$ and $2$ (which frequently arises in computer science), and particularly base $e$. The natural logarithm $\ln$ is defined to be $\log_e$.

Alternatively, the natural logarithm can be defined to be a primitive of the function $$f(t) = \frac{1}{t}$$ subject to the condition that $\ln{1} = 0$.

In the study of complex numbers, the solutions $a$ of $e^{a} = z$ are called complex logarithms. This uniquely specifies the modulus of $a$, but not its argument; as such, we define the principal logarithm $\operatorname{Log}(re^{i\theta}) = \ln{r} + i \theta$, with the restriction $-\pi < \theta \le \pi$ (or alternatively, $0 \le \theta < 2\pi$). This leads to a branch cut, or discontinuity - alternatively, the complex logarithm can be viewed as a multi-valued function.

Reference: Logarithm.

This tag often goes along with .

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How is $\ln(\sin 2x)^{\ln x} = \ln x \cdot \sin 2x$?

In my textbook, there's something like: $$\ln(\sin 2x)^{\ln x} = \ln x \cdot \sin 2x$$ I thought it should be $$\ln x\cdot \ln(\sin 2x).$$
Jiew Meng
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Logarithmic quotient

$$ \left(\frac25\right)\ln(1/2)+\left(\frac15\right)\ln(2) $$ Im having some difficulty with above quotient. Here is what i try to…
Pierre
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Changing base of a logarithm by taking a square root from base?

From my homework I found $$\log_9{x} = \log_3{\sqrt{x}}$$ and besides that an explanation that to this was done by taking a square root of the base. I fail to grasp this completely. Should I need to turn $\log_9{x}$ into base 3, I'd do something…
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Solve for $n$ in $4\log_2(n)=n,\,$ i.e. $\,n^4 = 2^n$?

As the title suggests, my log skills are pretty lacking. Need to learn how to get from $4\log_2(n)=n$ to $n=16$ ($\log$ base $2$). I've searched Google and it seems I am missing some core concept here. I really appreciate the help or guidance.
BajaBob
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How do you solve $x^{\log x}=100x$

How do you solve $x^{\log x}=100x$? Can you please thoroughly explain the left side of the equation. Please explain very clearly because I have only been learning logarithms for about a week.
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Simplifying an expression using a logarithm

I have the following expression $$\frac{1}{1+\rho}(1+n)^{(1-\sigma)}*(1+\gamma_{A})^{1-\sigma}<1$$ and have to use logarithms to get the following $$(1-\sigma)(n+\gamma_{A})<\rho$$ Could someone please offer me some help on how to do it? That's a…
wakum
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Please explain why $10$ raised to the power of $0$ ($10^0$) is equal to $1$

Please explain why $10$ raised to the power of $0$ i.e., $10^0$ is equal to $1$ and $10^1$ is simply equal to $10$, then the numbers between $1$ and $10$ can be written as $10$ raised to some power between $0$ and $1$.
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logarithmic inequality with different bases

I have problem with following inequality $\log_{4}{5}+\log_{5}{6}+\log_{6}{7}+\log_{7}{8} \ge 4.4$ I tried to change all logarithms to base $10$ but it didn't work
Mark
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problem with understanding logarithm

Could anyone explain why this is true?$$\log_{a}{b^{\log_{a}c}} = \log_{a}{c}\log_{a}{b}$$ I think it's related to $a^{\log_{a}{b}}=b$ but I can't link it ...
Mark
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Exact Solution for Logarithmic Equation?

I am faced with this equation, and I don't really know where to begin: $$x^2e^2 - 2e^x = 0.$$ I usually start these types of problems by factoring out a common term, but I don't see any in this particular example.
Chad
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Why isn't $2\log(-1)$ real?

In high school we learn that a $a\log[(x)] = \log (x^a)$ From this I would assume $2\log(-1) = \log [(-1)^2]$ However, the first is not real and the second is, according to my calculator and textbook. Why is this?
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Understanding why this natural log formula rewrite works

I came across this question in my homework and am unsure why it works this way. Given $y= \ln(e^{x^2})$, find the derivative. The given answer work showed the formula rewritten as $y=x^{2}$ before starting the differentiation process. My thinking…
Jason
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how to solve the following question using logarithms?

how can I use logarithms to compare a,b,c in an ascending order $$a=\frac{3^{8.7} - 3^{6.2}}{5}\\\ b=\frac{3^{11.7} - 3^{8.7}}{6} \\\ c=\frac{3^{11.7} - 3^{6.2}}{11} \\\ $$ i tried to simplify a b and c to get a constant that won't effect the…
lodo
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Solving $\log_3x^3 - 4\log_9x - 5\log_{27}x^{1/2} = \log_94$

Having trouble solving this simple logarithm problem: $$\log_3(x^3) - 4\log_9(x) - 5\log_{27}(x^{1/2}) = \log_9(4)$$ I’ve been stuck as I when I solve it I get an answer of $2$, when the actual solution seems to be $x=64$? Whilst editing and trying…
Harry
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Solving $\log_{x/2}(x+2)-\log_x(4-x)=1$

$$\bbox[aqua]{\log _{\frac{x}{2}}(x+2)-\log _x(4-x)=1}$$ $$\mapsto \log _{\frac{x}{2}}(x+2)=\log _x x+\log _x(4-x) \\\Rightarrow \log _{\frac{x}{2}}(x+2)=\log _x(x(4-x)) \\\Rightarrow \frac{\log _x(x+2)}{\log _x\left(\frac{x}{2}\right)}=\log…
Behnam
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