Questions tagged [logarithms]

Questions related to real and complex logarithms.

The logarithm is generally defined to be an inverse function for the exponential. If $x > 0$ is a real number and $b > 0$, $b \ne 1$, then the base-$b$ logarithm is defined by

$$\log_b(x) = y \iff b^y = x$$

The most commonly used bases are base $10$ and $2$ (which frequently arises in computer science), and particularly base $e$. The natural logarithm $\ln$ is defined to be $\log_e$.

Alternatively, the natural logarithm can be defined to be a primitive of the function $$f(t) = \frac{1}{t}$$ subject to the condition that $\ln{1} = 0$.

In the study of complex numbers, the solutions $a$ of $e^{a} = z$ are called complex logarithms. This uniquely specifies the modulus of $a$, but not its argument; as such, we define the principal logarithm $\operatorname{Log}(re^{i\theta}) = \ln{r} + i \theta$, with the restriction $-\pi < \theta \le \pi$ (or alternatively, $0 \le \theta < 2\pi$). This leads to a branch cut, or discontinuity - alternatively, the complex logarithm can be viewed as a multi-valued function.

Reference: Logarithm.

This tag often goes along with .

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How can I re-write $2^{\sqrt{\log n}}$ as $n^?$

How can I re-write $2^{\sqrt{\log n}}$ as $n^?$ I tried $2^{\log n^{0.5}}$ then $2^{0.5\log n}$, then $n^{0.5 \cdot 1} = \sqrt{n}$. But it seems to be smaller than $\sqrt{n}$ in the answers sheet.
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Re-write $\log n^{\log n}$ as $n^{\log(\log n)}$

Re-write $(\log(n))^{\log n}$ as $n^{\log(\log n)}$ I have not managed to re-write it, the only rule I thought of is to write it as $\log(n)\log(n)$ but I've no idea how to bring the $n$ as the basis.
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Properties of Logarithmic Equations (Help)

Can someone please explain to me how the last step in this simplification works. $$2^x = x^2$$ $$\implies \ln(2^x) = \ln(x^2) \quad \forall x \ne 0 $$ $$\implies x \ln(2) = 2 \ln(x) $$ $$\implies \ln(x) = {2x \over \ln(2)} \quad \textbf…
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Solving the exponential equation $2e^x (x-1)=0$

How does one solve the equation $2e^x (x-1)=0$ ?
user6254
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$\log_{4n} 40\sqrt{3} = \log_{3n} 45$, find $n^3$.

$\log_{4n} 40\sqrt{3} = \log_{3n} 45$, find $n^3$. I can't seem to find any identities to help me in this problem. Any hints or answers? Thanks in advance!
user359548
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How to compute exponents?

I read How to figure out the log of a number without a calculator? but what is actually used to compute the basic tables themselves, Newton's method or Taylor series? If Taylor series is used then how is it done? Does a calculator use the Taylor…
reori
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Natural log & L'Hopitals $x^x$

I need someone to tell me the step I'm missing or doing incorrectly. The problem is: $$\lim _{ x\rightarrow 0 }{ { x }^{ x } } $$ $1$. $\ln x^x$ $2$. $x\ln { x } $ $3$. This is the step I don't follow: $\frac { \ln { x } }{ \frac { 1 }{ x }…
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Prove $pq + 5(p - q) = 1$

Could you please explain me how to solve: If $p\:=\:\log _{12}\left(18\right)$ and $q\:=\:\log _{24}\left(54\right)$, $pq\:+\:5\left(p-q\right)\:=\:1$ I tried this way: $p =…
SuperMan
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How do I solve this tricky logarithmic formula

I have a formula as follows: $0.55508389365 = \ln(20 + x)/\ln(240 +x)$ I happen to know that x = 1 (approximately) is the solution. But I'm not sure how I would go about solving this if I didn't know the answer. By messing around with log…
Martin
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Defining logarithms explicitly

How are logarithms defined explicitly? One way I can come up with is the following, first start by using McLaurin series representation of exponent function: $$e^x = \sum_{k=o}^{\infty}\frac{x^k}{k!} = 1 + x + \frac{x^2}{2!} +…
Dole
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Basic Logarithms problems

Can someone tell me how many digits would be there in- $(2.5)^{200}$ and $6^{50}? $ I'm utterly confused where to begin from. Any help would be appreciable.
Zlatan
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Solve $3^{x+2}\cdot4^{-(x+3)}+3^{x+4}\cdot4^{-(x+3)} = \frac{40}{9}$

Can someone point me in the right direction how to solve this? $3^{x+2}\cdot4^{-(x+3)}+3^{x+4}\cdot4^{-(x+3)} = \frac{40}{9}$ I guess I have to get to logarithms of the same base. But how? What principle should I use here? Thx
Smejki
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Subtracting Multiple Logarithms

I am asked to simplify $$J=\ln (x^2-16)-\ln x-\ln(x-4), \quad x>4$$ Since each logarithm's argument is non-negative, I can use $$\ln x -\ln y=\ln\frac{x}{y}$$ and obtain the correct answer $$\ln\frac{x+4}{x}$$ However I tried to get the answer by…
Jacob
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Logarithmic square

I can't understand if there is any such formula for $(\log_{b}a)^2$. Are there any? $\log_{b}(a^2) = 2\log_{b}{a}$ But if the whole log is squared is there any such formula or the same formula is used?
Ritwika
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Finding the solution of logs and exponentials equations to 2 decimal places

I'm going through maths textbooks at a rather fast pace at the moment as I have been accepted to take my chemical engineering PHD in Melbourne next year. I have been doing really well at the log rules and applying these, surprising myself in some…