Questions tagged [logarithms]

Questions related to real and complex logarithms.

The logarithm is generally defined to be an inverse function for the exponential. If $x > 0$ is a real number and $b > 0$, $b \ne 1$, then the base-$b$ logarithm is defined by

$$\log_b(x) = y \iff b^y = x$$

The most commonly used bases are base $10$ and $2$ (which frequently arises in computer science), and particularly base $e$. The natural logarithm $\ln$ is defined to be $\log_e$.

Alternatively, the natural logarithm can be defined to be a primitive of the function $$f(t) = \frac{1}{t}$$ subject to the condition that $\ln{1} = 0$.

In the study of complex numbers, the solutions $a$ of $e^{a} = z$ are called complex logarithms. This uniquely specifies the modulus of $a$, but not its argument; as such, we define the principal logarithm $\operatorname{Log}(re^{i\theta}) = \ln{r} + i \theta$, with the restriction $-\pi < \theta \le \pi$ (or alternatively, $0 \le \theta < 2\pi$). This leads to a branch cut, or discontinuity - alternatively, the complex logarithm can be viewed as a multi-valued function.

Reference: Logarithm.

This tag often goes along with .

10168 questions
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What is the difference in this question between $\log$ and $\lg$?

Am I right in assuming that $\lg$ just refers to $\log$ base ($10$)? Whereas $\log$ is just any unspecified log? I'm solving $\lg{15}-\lg{5}$ Am I good to just use the standard rules of logarithms, where subtraction is concerned?
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Logarithm problem question

$$a^{bx} = c$$ Solve for x $$\log a^{bx} = \log c$$ $$bx \log a = \log c$$ $$x = \frac{\log c}{b \log a}$$ Is this correct? Thanks :)
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Cancelling a logarithm

I was wondering if there was a way to cancel out a logarithm? For example: $\log_a A$ > $\log_a B$ What would a have to be for the log to go away and be left with A > B? Thanks in advance!
Alex
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Show $(\log n)^{ (\log n) } = 2^{(\log n)(\log (\log n))}$

I am having difficulty understanding how this follows. $$(\log n)^{ (\log n) } = 2^{(\log n)(\log (\log n))} = n^{\log \log n}$$ Which logarithmic identities are used to go through each equality? e.g. how do you first go from $$(\log n)^{ (\log n)…
T. Webster
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Logarithm question with base change

If $\log_{12} 27 = a$ then find the value of $\log_6 16$.
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Please explain the logarithmic equation

The default equation is $(1 + x)^3=4^{-y^2} $ I solved as follows: $(-3\log_4(1+x))^{1/2}=y$ With the logarithm base equal to $4$, my idea is that $4$ is the number we have in the right part of the equation, that's why I went with $4$; And I…
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$2\ln(-x) \neq \ln(-x^2) ? $

I know the rule $$n\ln(x) = \ln(x^n)$$ But this doesn't apply to $$2\ln(-x) = \ln(-x^2)$$ Can you see what I'm not understanding?
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Really simple question: Add $\bar4.74628$ and $ 3.42367$ .I just need to cross check answer.

Add $\bar4.74628$ and $ 3.42367$ This question is about characteristics and mantissa. I thought my book has written the wrong answer in the example. I just wish to cross check because this seem like something a kid would ask. They do it like…
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Adding logarithms with different bases

Just had an exam, this sinister question I know I did wrong lingers in my mind: Solve for $x$, $$2-\log_3(x-7) = \log_{\frac{1}{3}} (2x)$$ On phone not sure how to write the equation properly. Please correct and take me through solving the problem.…
Wharf Rat
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How to simplify the expression $(\log_9 2 + \log_9 4)\log_2 (3)$

Our test asked to simplify $(\log_9 2 + \log_9 4)\log_2 (3)$. I simplified the first parenthesis to be $\log_9 (8)$. So, now I have $\log_9 (8) \cdot \log_2 (3)$ and I can change to base $10$ and get, $$\frac{\log 8}{\log 9} \cdot \frac{\log 3}{\log…
user163862
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Verify whether or not expression is true or not for z>0

I need to verify whether or not the below expression is true or not for $z>0$. I'm trying to understand the rules of logarithms but I can't figure out how to apply it myself or where to even begin. $$\log_5 (z)+\log_{25} (z)= \frac{3}{2}\log_5…
Lisa
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Solution of $5^{\log x}+5x^{\log 5}=3$

Solve for $x$ $$5^{\log x}+5x^{\log 5}=3$$ where base of log is $a$, $a>0$ and $a \neq1$ Could someone hint as how to initiate this question? I am not having any idea as how to proceed.
H.P. Das
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How to solve $y= x \cdot 2^x$ for x

Can anyone help me solve this for $x$: $y= x \cdot 2^x$ I know for $y= 2^x$, that $\log_2(y) = x$ And I can get $\displaystyle \frac yx = 2^x \implies \log_2 \frac yx = x $ But I can't condense to only a single $x$ in the equation.
David
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Deformations in Variational Bayesian method

I'm studying Topic Model, but I can't understand the following transformations. $F$ is variational lower bound. $$\begin{eqnarray} F[q(z_{1:n}, \phi, \pi)] &=& \int \sum_{z_{1:n}} q(z_{1:n}) q(\phi) q(\pi) \log \frac{p(x_{1:n}, z_{1:n} | \phi, \pi)…
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Finding a solution to this logarithm equation.

How is: $ \log_{(xyz)^{1/3}} \left(\frac{yz}{x^{3}}\right)^{2}$ expressed in terms of a and b when: $ a = \log_{y} x $ $ b = \log_{z} x $ EDIT: It is z in the numerator, apologies i posted by memory. Also reframed the question.
McTaffy
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