Questions tagged [logarithms]

Questions related to real and complex logarithms.

The logarithm is generally defined to be an inverse function for the exponential. If $x > 0$ is a real number and $b > 0$, $b \ne 1$, then the base-$b$ logarithm is defined by

$$\log_b(x) = y \iff b^y = x$$

The most commonly used bases are base $10$ and $2$ (which frequently arises in computer science), and particularly base $e$. The natural logarithm $\ln$ is defined to be $\log_e$.

Alternatively, the natural logarithm can be defined to be a primitive of the function $$f(t) = \frac{1}{t}$$ subject to the condition that $\ln{1} = 0$.

In the study of complex numbers, the solutions $a$ of $e^{a} = z$ are called complex logarithms. This uniquely specifies the modulus of $a$, but not its argument; as such, we define the principal logarithm $\operatorname{Log}(re^{i\theta}) = \ln{r} + i \theta$, with the restriction $-\pi < \theta \le \pi$ (or alternatively, $0 \le \theta < 2\pi$). This leads to a branch cut, or discontinuity - alternatively, the complex logarithm can be viewed as a multi-valued function.

Reference: Logarithm.

This tag often goes along with .

10168 questions
4
votes
3 answers

Logarithmic expression how to simplify

$$ \log_{3}24 - 3\log_{3}5\times \log_{5}2$$ What I can get is: $$ \log_3{24} - \log_3{5^3} \times \log_{5}2$$ Change of base rule to get it all in base 3: $$ \log_5{2} = \frac{\log_3{2}}{\log_3{5}} $$ Now I have: $$\log_3{24} -…
4
votes
2 answers

Does $\log_1{n}$ have any analytical significance in counting digits of unary numbers?

If $\lfloor{\log_b{n}}\rfloor+1$ counts the number of digits required to represent a number $n$ of radix $b$, what is the significance of $\log_1{n}$ in terms of counting digits of unary numbers? For…
4
votes
2 answers

How to solve this logarithm equation?

How can I solve it? $$ \frac{2}{\log_{8}(x-1)} - \frac{2}{\log_{8}(x )} =1$$ I don't have idea how to solve it and I will be happy for help about this exercise.
4
votes
1 answer

Why isn't $\log_1 (1) = 1$?

Exponential form: $a^b = c$. Logarithmic form: $\log_a(c) = b$. $1^1 = 1$; therefore, $\log_1(1) = 1$, but it isn't. Furthermore, isn't the result of $\log_x(x)$ always 1? Why is there an error? What am I actually doing in $\log_1(1)$?
Chris K
  • 63
  • 7
4
votes
2 answers

Solve $\ln \,\ln \big(n^{\frac{1}{2^{k}}}\big)=\ln\,\ln\,(n)-k\,\ln 2$.

Question While solving a Recurrence Relation, I got stuck at some Logarithmic equation.For this i have to prove $$\ln \,\ln (n^{\frac{1}{2^{k}}})=\ln\,\ln\,(n)-k\,\ln 2$$ My Approach $$\ln \,\ln (n^{\frac{1}{2^{k}}})=\frac{1}{2^{k}}*\ln…
laura
  • 2,530
4
votes
4 answers

Does $\log _b \left( x \right) = \log _b \left( y \right) \rightarrow x = y$?

I hit a snag whilst revising some log rules, could anyone confirm my suspicion: $$\log _b \left( x \right) = \log _b \left( y \right) \rightarrow x = y ?$$
Danny King
  • 1,953
4
votes
1 answer

How to solve this equation using $ \log $?

I am new to logarithms, and I came across this equation.. $$ \ (3)^{4x} - (3)^{(2x + \log_3(12))} +27 = 0 \ $$ I need a way to simply things as this seems very complex Edit: I tried $$ \ (3)^{4x} + 27 = (3)^{(2x + \log_3(12))} \ $$ So $$ \…
Fghj
  • 1,471
4
votes
1 answer

Prove that $\log_{2b+c}a+\log_{2c+a}b+\log_{2a+b}c\ge\frac{3}{2}$

Let $a\ge 3,b\ge3,c\ge3$. Prove that: $$\log_{2b+c}a+\log_{2c+a}b+\log_{2a+b}c\ge\frac{3}{2}$$ I don't know what to do. Rewrite to $\ln(x)$ or $e^x$ But it's not work
4
votes
6 answers

Equation which has to be solved with logarithms

I need some help how to solve these equations for $x$. I think I have to use logarithms but still not sure how to do it and would be really grateful if someone could explain me. $x^2 \cdot 2^{x + 1} +2 ^{\lvert x - 3\rvert + 2} = x^2 \cdot…
SuperMan
  • 303
4
votes
3 answers

What is the inverse function of $\alpha\mathrm{e}^{\beta x}+\gamma\mathrm{e}^{\delta x}$?

I need to solve this equation for $x$: $\alpha\mathrm{e}^{\beta x}+\gamma\mathrm{e}^{\delta x}=\epsilon$ ($\alpha$, $\beta$, $\gamma$, $\delta$, $\epsilon$ are real constants) I'm only interested in real solutions. Is such an equation solvable? Even…
gaazkam
  • 903
4
votes
2 answers

Prove: $\log _{c+b}\left(a\right)+\log _{c-b}\left(a\right)=2\log _{c+b}\left(a\right)\cdot \log _{c-b}\left(a\right)$, where $a^2 + b^2 = c^2$

Could you help me proving this? $$\log _{c+b}\left(a\right)+\log _{c-b}\left(a\right)=2\log _{c+b}\left(a\right)\cdot \log _{c-b}\left(a\right)$$ where $c$ is the length of the hypotenuse of a right triangle, and $a$ and $b$ are the lengths of…
SuperMan
  • 303
4
votes
2 answers

$2^n=n$ and similar equations

Is it possible to solve equations in the form $k^n=n$ for n and if so, How? I am new to logarithms and so would be glad if someone could explain even if there is an obvious answer. Also What about $k^{a+b}=a$ for a? Or $k^{ab}=a$?
4
votes
1 answer

$x+\ln(x)=0$, what is $x$?

My friend came across this strange equation and I cant find mathematical way to find $x$ without drawing $x$ and $-\ln(x)$ and see that they come across at almost $x=0.5$. Can any one help?
Stav Alfi
  • 785
4
votes
3 answers

Solving logarithmic equation $2\log(x) + 1 =\log(19x+2)$

I'm stuck trying to solve $$2\log(x) + 1 =\log(19x+2)$$ I know the solution has to be $x = 2$. However I can't find the manual steps (Wolfram doesn't know the manual steps either). This is all I got $$\log(x^2) + 1 = \log(19x +2)$$ $$\log(x^2) -…
Ayy
  • 158