Questions tagged [partial-derivative]

For questions regarding partial derivatives. The partial derivative of a function of several variables is the derivative of the function with respect to one of those variables, with all others held constant.

The partial derivative of a function of several variables is the derivative of the function with respect to one of the variables, with the others held constant. The partial derivative, like the ordinary derivative, describes the rate of change of a function in a particular direction.

If $f = f(a_1, a_2, \dots, a_n)$ is a function of $n$ variables, then the partial derivative of $f$ with respect to the variable $a_i$ can be written as a limit:

$$\frac{\partial f}{\partial a_i} = \lim_{h \to 0} \frac{f(a_1, \dots, a_i + h, \dots, a_n) - f(a_1, \dots, a_i, \dots, a_n)}{h}.$$

Alternatively, this quantity can be denoted as $f_{a_i}$.

If the function has continuous partial second derivatives, then:

$$\frac{\partial}{\partial x_i}\left(\frac{\partial}{\partial x_j}\right)=\frac{\partial}{\partial x_j}\left(\frac{\partial}{\partial x_i}\right)$$

a result known as Schwarz's Theorem.

6917 questions
0
votes
1 answer

Help with partial differentiation

I posted this problem earlier today, but now I have some other questions regarding the problem. $$F(x,y)=\begin{cases} f(x,y) & (x,y)\neq (0,0) \\ 0 & (x,y)=0 \end{cases}$$ where $f(x,y)=\frac{x^2y}{x^2+y^2}$ *1.) Determine if f is…
0
votes
1 answer

gradient of the normalized cross product

Can someone be so kind to verify the derivation of the gradient of a normalized cross product? I have translated the pseudo code from "Position Based Dynamics" to working code, but the Bending Constraint Projection section gives me headaches - last…
Toorop
  • 11
0
votes
5 answers

a small doubt with partial derivative

This is is pretty straightforward. I have a function, say $X = X(q)$. And $q=q_1+q_2(q_1)$. So X is a function of q, and q is a function of $q_1,q_2$. But $q_2$ is also a function of $q_1$. Now calculate $\frac{\partial X}{\partial q_1}$ I proceed…
0
votes
0 answers

How to take derivative with respect to a variable of a function of two variables and another function

I have a function $f(x-a,y-b\frac{1}{g(x,y)})$. I want to find the partial derivative of this function with respect to $x$. But I am literally lost. Can you give me any insight on the solution?What I could do so far is as follows: $$\frac{\partial…
starhd
  • 1
0
votes
1 answer

How to approach a directional derivative as u varies

Find the maximum and minimum values of the directional derivative Duf at (1/2, 1) as u varies for the function f(x,y)= x3 -xy2-4x2+3x+x2y What im not sure about is the phrase as u varies. I understand the formula for directional derivatives is…
DDDDOO
  • 97
0
votes
1 answer

Partial derivative of double sum of cosine

I have a problem calculating/verifying the partial derivative below: $$ \frac{\partial}{\partial{\phi_k}} \sum_{i=1 } ^{N} \sum_{j=1}^{N}\cos{(\phi_i-\phi_j})$$ My result, after doing the expansion for specific values of $i,j=1,2,3$ e.g., and…
noir
  • 1
0
votes
0 answers

Partial derivative of mean of some variable

I don't get the following $$ \frac{\partial z}{\partial x} = \frac{\partial}{\partial x}\left[\frac{1}{n}\sum_i^n x_i^2\right] = \frac{x}{2} $$ Here x is a list of numbers (matrix or vector). In my opinion it should be something…
0
votes
0 answers

Solve $n$. $\varphi = n[\ln(\alpha) - \ln(x)]$, where $\varphi = \frac{\partial [\ln(x)]}{\partial [\ln(y)]}$.

Question: Solve for $n$. $\varphi = n[\ln(\alpha) - \ln(x)]$, where $\varphi = \frac{\partial [\ln(x)]}{\partial [\ln(y)]}$. Solution: Eq. 1: $\varphi = n[\ln(\alpha) - \ln(x)]$ Substitute $\varphi$ from Eq. 1 to Eq. 2: Eq. 2: $\frac{\partial…
0
votes
1 answer

Why is the cyclic relation of partial derivatives correct?

I was studying this theorem and am struggling to understand the proof: The proof I studied is as follows: It is given that $f=f(x,y) $. let $f=z \quad \rightarrow \quad dx=(\frac{\partial x}{\partial y})_z \ dy+(\frac{\partial x}{\partial z})_y \…
0
votes
2 answers

Calculate $z_x+z_y$ at point $( \frac{\pi +3}{3}, \frac{\pi+1}{2})$, if $z=uv^2$, $x=u+\sin v$ and $y=v+\cos u$

I have no idea how to calculate $z_x+z_y$ at a point $\left( \frac{\pi +3}{3}, \frac{\pi+1}{2}\right)$, if $z=uv^2$ and $x=u+sinv$, $y=v+cosu$. $z$ is not expressed in terms of $x$ and $y$. Maybe it is meant to be solved as $x_u=1$ and $x_v=cosv$,…
user
  • 1,412
0
votes
0 answers

chain rule in partial differentiation

if $w=x^2-2xy+3y^2,x=uv$ and $y= u^2-v^2$,use the chain rule to find $\frac{dw}{du}$ and $\frac{dw}{dv}$. Here is what I did \begin{alignat}{2}\frac{\partial w}{\partial u}&= \frac{\partial w}{\partial x}\frac{\partial x}{\partial u} +…
0
votes
0 answers

Is it possible to interchange mixed derivative in the convection equation?

Let the convection equation $\frac{\delta u}{\delta t} + c\frac{\delta u}{\delta x} = 0$. I want to show that $$\frac{\delta^2 u}{\delta t^2}-c\frac{\delta^2 u}{\delta x^2}=0$$ I think it would be possible to differentiate the original convection…
alryosha
  • 563
0
votes
2 answers

second total derivative of 3 variables

I have a function: $$r=\sqrt{x^2+y^2+z^2}$$ and wish to calculate: $$\frac{d^2r}{dt^2}$$ so far I have said: $$\frac{d^2r}{dt^2}=\frac{\partial^2r}{\partial x^2}\left(\frac{dx}{dt}\right)^2+\frac{\partial^2r}{\partial…
Henry Lee
  • 12,215
0
votes
0 answers

partial derivative with 2 variables

I have a function f(x,y) with 2 variables x and y. I calculate the partial derivative and get the following equation $$\frac{\partial f (x,y)}{\partial x}=g(y)=0$$ To solve the problem $$g(y)=a+\frac{b}{log(1+y)}+\frac{c~y}{log(1+y)}=0$$ can I use…
user363001
0
votes
1 answer

if x=f(u,v) and y=g(u,v), find ∂u/∂x and ∂v/∂x

I encountered this problem and tried to partially differentiate both equations against x and see if i can create simultaneous equations to solve for the two, but I don't seem to be getting anywhere and now I'm not sure how I should start.