Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

26755 questions
1
vote
1 answer

solving a simple polynomial equation?

I am looking for a solution to an equation of the form $a x^4 + b x + c = 0$. (I need the positive solutions only, but I can filter the negative ones out, if I get the four solutions for the above.) Is there a general way to derive a solution for…
1
vote
1 answer

Show that $\frac p{a^n}-\frac q{b^n}-1=0$.

If $x^n-py^n-qz^n$ is exactly divisible by $x^2-(ay+bz)x+abyz$ , then prove that $\frac p{a^n}-\frac q{b^n}-1=0$
Snehil Sinha
  • 1,179
1
vote
0 answers

Polynomial addition using linked lists (theory only)

Someone on Stackoverflow suggested posting here. I have an Algorithms test coming up for my Software Engineering course, but the book and lecture notes don't explain the theory behind summing polynomials using linked lists (No joke, they really…
Cammers
  • 11
  • 1
1
vote
1 answer

Expanding brackets

My question today is whether or not it is in mathematical convention to do the following when expanding brackets. If we have the expression $(x+2)(x-5)$ and we expand this out, we get $x^2-3x-10$. Would it go against mathematical convention to write…
1
vote
1 answer

Find the unique degree $6$ polynomial

What makes it unique is the following requirements on the polynomial: It's coefficients are either $0$ or $1$ It has no rational roots The absolute value of $p(x)$ isn't prime for every integer. Just for this problem, $1$ isn't a prime.
1
vote
1 answer

How prove $x^{k+1}|[(x-1)f(x)+(x+1)^{k+n+1}]$

let $$f(x)=\sum_{i=0}^{k}(2x)^i(x+1)^{k+n-i}$$ show that $$x^{k+1}|[(x-1)f(x)+(x+1)^{k+n+1}]$$ my idea:since…
math110
  • 93,304
1
vote
3 answers

Factor theorem and zeroes of a polynomial

What should be added to $x^3-2x^2-12x-9$ such that it is completely divisible by $x^2+x-6$? I factorized $x^2+x-6$ as $(x+3)(x-2)$. I am unable to understand how to make use of factor theorem to arrive at the solution of this problem. But by actual…
1
vote
3 answers

Zero of Polynomial

If $(a-b)$, $a$, and $(a+b)$ are the zeroes of the polynomial $x^3-3x^2+x+1$ then what are the values of $a$ and $b$? I have taken $f(x)=x^3-3x^2+x+1$ and equated $f(a-b)$, $f(a)$ and $f(a+b)$ to zero. But I could not reduce the equations.
1
vote
1 answer

Polynomial expansion need help

What is the answer to this my calculator is giving me different answers $$(-0.2511x^3 + 0.5766x^2 + 0.1744X + 2.7)^2$$
1
vote
1 answer

$\text{Gal}(L|K)$ not abelian

$f \in K[X]$ is irreducible and separable. $L$ the splitting field of $f$. Show: $[L:K] > \text{deg}(f)$ $\Rightarrow$ $\text{Gal}(L|K)$ is not abelian
1
vote
1 answer

polynomial with integer coefficients divided by $x^3 -x$

Let $f(x)$ be a polynomial with integer coefficients. Assume that 3 divides the value of $f(n)$ for each integer $n$. prove that when $f(x)$ is divided by $x^3-x $ , the remainder is of the form $3r(x)$, where $r(x)$ is a polynomial with integer…
user71408
1
vote
6 answers

Factor a quadratic equation to get two binomials

I'm wrestling with this quadratic and trying to figure out how to factor it: $$3x^2 - 5x + 2 = 0$$ I know that the product of the last terms of the binomial for an equation equals the third term of the polynomial. Also, the sum of the products of…
Alex
  • 259
1
vote
1 answer

I am trying to solve a problem about polynomial division. I must get the original plynomial from the rest.

The exercise is as follows. There is a fourth degree polynomial, that when divided by $(x - 3)$ has a $r_1 = 100$, and when divided by $(x + 1)$ a $r_2 = -4$. And the question is what would the rest be when divided by $(x - 3)(x + 1)$. I have tried…
Rptx
  • 111
1
vote
3 answers

Find Polynomial coefficients

How can I find the real coefficients a,b if the polynomial $ P(X)=X^4-5X^3+8X^2+aX+b $ is divisible by $ Q(X)=(X-1)^2 $ So if 1 is a solution, I get a+b=-4; where should i look for other roots?
1
vote
2 answers

Find the value of the real parameters a,b, if there exists a P(X) binomial and the following is true

Find the value of the real parameters a,b, if there exists a P(X) binomial and the following is true $(X^3-aX^2-bX+1) : P(X) = X^2-X+1 $ I tried to divide and to equalize the remainder to zero, but I think i'm missing something.