Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

26755 questions
1
vote
0 answers

Why does the calculation of a polynomial according to Horner’s rule include the division by polynomials of form x-b?

Some textbook (Höhere Mathematik 1, Meyberg/Vachenauer, 6th edition) states that the calculation of the functional values of a polynomial $f\colon \mathbb R\rightarrow\mathbb R$, $f(x) = a_0 + a_1x + a_2x^2 + \cdots + a_nx^n$, $n\ge1$, $a_i…
1
vote
0 answers

An polynomial identical equation

Given positive integer $n$. Let perfect polynomials be polynomials on $\mathbb{C}$ which can be written as $P_1^n+\cdots+P_n^n$, where $P_i\in\mathbb{C}[x]$. Prove that the product of $n$ perfect polynomials is still perfect number. I think the…
OrthoPole
  • 107
1
vote
2 answers

Find the polynomials $P \in \Bbb{R}[X]$ so that $(X+4) P(X)=X P(X+1)$.

Find the polynomials $P \in \Bbb{R}[X]$ so that $(X+4) P(X)=X P(X+1)$. I haven't gotten very far: $$(0+4)P(0)=0P(0+1) \iff P(0)=0$$ Through $P(0)=0$, we can derive $P(-1)=0$: $$(-1+4)P(-1)=-1P(-1+1)=-P(0)=0 \iff P(-1)=0,$$ also $P(-2)=0$ and…
1
vote
3 answers

Prove that 1 is a triple root of a polynomial

I'm studying for an exam and trying to prove whether 1 is a triple root for the polynomial: $$x^{2n+1}-(2n+1)x^{n+1}+(2n+1)x^n-1$$ for every $n\geq1$. In our math class we never solved such a problem. So far we only used horner's scheme to prove…
Jane
  • 11
1
vote
1 answer

Let $f(x)=a_0+a_1x+a_2x^2....+a_nx^n$, where $a_i$ are non-negative integers. If $f(1)=21$ and $f(25)=78357$, find the value of $\frac{f(10)+3}{100}$

Let $f(x)=a_0+a_1x+a_2x^2....+a_nx^n$, where $a_i$ are non-negative integers for $i=0, 1, 2,...., n$. If $f(1)=21$ and $f(25)=78357$, find the value of $\frac{f(10)+3}{100}$ My work-- Let $f(x)-21=g_1(x)\Rightarrow g_1(1)=0$. This implies that $1$…
An Alien
  • 516
1
vote
1 answer

Finding polynomials so that $m=af+bg$

Let $$ f(x)=3x^4 -2x^3-6x^2+7x-2 $$ and $$ g(x)=3x^4 -8x^3+13x^2-12x+4 $$ I want to find two polynomials $a$ and $b$ so that $$ m=af+bg $$ whereas $m$ is the greatest common divisor. With some basic algebra, I got…
1
vote
1 answer

$x^n + px - q = 0$ has a double root

Problem: The equation $x^n + px - q = 0$ has a double root. Show that $\left(\dfrac{p}{n}\right)^n + \left(\dfrac{q}{n-1}\right)^{n-1} = 0$. My attempt: Let the double root be $\alpha$ and $P(x) = x^n + px - q$, then $P(\alpha) = 0$ and $P'(\alpha)…
1
vote
1 answer

$x^6+3ax^4+3x^3+3ax^2+1$ is irreducible in $\Bbb Q$, where $a$ is a positive integer.

$x^6+3ax^4+3x^3+3ax^2+1$ is irreducible in $\Bbb Q$, where $a$ is a positive integer. How to prove it? Clealy, $f$ has no rational roots, so how to derive contradiction if $f(x)=g(x)h(x)$, where the degree of $g,h$ are $2,4$ (or $3,3$) respectively?
xldd
  • 3,407
1
vote
0 answers

$f_{n}\left ( x,y \right )+f_{n-1}\left ( x,y \right )$ is irreducible for two homogeneous polynomials without common divisor.

I want to prove that for an integer $n\geq 2$, $f_{n}\left ( x,y \right )$ and $f_{n-1}\left ( x,y \right )$ are two homogenuous polynomials without common divisor whose degree are n and n-1 respectively, how to prove that $f_{n}\left ( x,y \right…
1
vote
1 answer

for a polynomial $f(x)$, $y^3+f(x)$ can be written as the product of two polynomial iff $f=g^3$

If f is a polynomial with one variable, then I want to prove that $y^3+f(x)$ can be written as the product of polynomials with positive degree if and only if there is a polynomial g(x) such that $f(x)=g(x)^3$, one direction is simple, if…
1
vote
0 answers

$(x^m+a^m,x^n+a^n)=x^d+a^d$, for complex $a\neq 0$

$(x^m+a^m,x^n+a^n)=x^d+a^d$, for complex $a\neq 0$, where $m,n$ are postive integers, $d$ is the gcd of $m,n$, and $m/d, n/d$ are both odd numbers. Clearly, let $m=m_1d, n=n_1d$, then $m_1,n_1$ are odd numbers, so…
xldd
  • 3,407
1
vote
1 answer

Regarding the meaning of remainder polynomial

Consider a polynomial $f(x)$. It can expressed in the form $$f(x) = \mu(x) g(x) + r(x)$$ where degree of $f(x) ≥$ degree of $g(x)$. Remainder when $f(x)$ is divided by $g(x)$ is graphically given by the curve joining the points $f(α_1)$, $f(α_2)$,…
1
vote
2 answers

Given a polynomial $W(x)$. Find all pairs of integers $a,b$ that satisfy $W(a)=W(b)$

Given a polynomial $W(x) = x^4-3x^3+5x^2-9x$. Find all pairs of distinct integers $a,b$ that satisfy $W(a)=W(b)$. My approach was to factor the polynomial. $$\begin{align*} x^4-3x^3+5x^2-9x &= (x^4-3x^3+2x^2)+(3x^2-9x+6)-6\\ &=…
1
vote
1 answer

Quadratic equation having roots are symmetric/non-symmetric function of another quadrating equation

Bit curious to know why these equations tend to behave like this. Let $f(x)=x^2+3x+2=0•••(1)$ be a function whose two roots are $\alpha=-1$ and $\beta=-2$. $\therefore \alpha+\beta=-3$ and $\alpha\beta=2$ Another equation whose roots are symmetric…
MSKB
  • 305
1
vote
0 answers

Polynomial with "quarter square" coefficients

I have encountered some polynomials in my work that have the following form: $n=2$: $1$ $n=3$: $\phi^2 + 2\phi + 1$ $n=4$: $\phi^4 + 2\phi^3 + 4\phi^2 + 2\phi + 1$ $n=5$: $\phi^6 + 2\phi^5 + 4\phi^4 + 6\phi^3 + 4\phi^2 + 2\phi + 1$ $n=6$:…