Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

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Polynomial fixed point lemma, $p(p(\dots p(t))) = t \Rightarrow p(t)=t \vee p(p(t))=t$

Does the following result: $$[ \ p(p(\dots p(t))) = t \ ] \Rightarrow [ \ p(t)=t \vee p(p(t))=t \ ]$$ (where $p$ is of course a polynomial) have a name? I need a (preferably elementary) proof of this. The LHS is the polynomial composed with itself…
Spine Feast
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An elementary proof for polynomials

(Problem) $f(x)=\sum\limits_{k=0}^n a_kx^k$ be a polynomial of real coefficients which satisfies $a_0=1$ and $deg(f(x))=n$. Show that there exists a complex number $\alpha$ satisfying $|f(\alpha)|\geq1 \land |\alpha|=1$. (My Solution 1) (Lemma$1$:…
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Polynomial division by polynomial without remainder

I have two polynomials: $$ Q(x)=x^{624} + x^{524} + x^{424} + x^{324} + x^{224} + x^{124} + x^{n} $$ $$ P(x) = x^{6} + x^{5} + x^{4} + x^{3} + x^{2} + x + 1 $$ And the question: what is the largest natural value of the number $n \leq 100 $ at which…
Noerigarnhy
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$f(x) = x^3 + ax^2 + bx + c$; the roots of $f(x)=0$ are 1, $k$, $k+1$. When $f(x)$ is divided by $x-2$, the remainder is 20. Show that $k^2-3k-18=0$.

This is in an IGCSE additional math question relating to factor and remainder theorem. My attempt: Using factor theorem we know that $f(1)=0$, $f(k)=0$ and $f(k+1)=0$. Using remainder theorem we know that $f(2)=20$. From this we can form the…
CroW
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How can other unknowns be calculated in polynomial division given there are no remainders?

I’ve being practicing polynomial long division for the last week and have built some competence/confidence around the algorithm for performing the operation, but this is stumping me: Given P($x$) = $(x^3-2x^2-x+2)/(x-k)$ has three values for k in…
duckegg
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Showing that constant term of the polynomial satisfy the below inequality

If a polnomial $R(x)$ of ninth degree satisfies $|a_9x^9 + a_8x^8+..a_0|$ $\leq$ $1$ $\forall$ x $\in$ $[-1,1]$ - {${0}$} , then show that $a_0$ satisfies $|a_0| \leq 1$. And does equality every achieved ? This was originally from a problem: …
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If $p(x)=ax^3 -2x^2 +bx+c$, find $a, b$ and $c$ if $p(0)=12$, $p(-1)=3$ and $p(2)=36$

If $p(x)=ax^3 -2x^2 +bx+c$, find $a, b$ and $c$ if $p(0)=12$, $p(-1)=3$ and $p(2)=36$ Can someone please teach me how to do this question thanks!
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How are the roots of a complex polynomial of degree > 4 actually found

I know that there are no general formulas for finding the roots of a complex polynomial of degree greater than 4. This site contains many questions about the roots of specific polynomials in this category. The fundamental theorem of algebra says…
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Given polynomials $p(x)$ and $q(x)$. If $z_1, z_2, z_3, z_4$ are roots of $q(x)$, then find the value of $p(z_1)+p(z_2) +p(z_3) +p(z_4)$.

Let $p(x)=x^6-x^5-x^3-x^2-x$ and $q(x)=x^4-x^3-x^2-1$. If $z_1, z_2, z_3, z_4$ are roots of $q(x)$, then find the value of $p(z_1)+p(z_2) +p(z_3) +p(z_4)$. My attempt: Dividing $p(x)$ by $q(x)$ gives $$p(x)=(x^2+1) \cdot q(x) +(x^2-x+1)$$ So, if $z$…
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Finding a remainder of the result of polynomials division if the dividend is unknown

Problem: If a polynomial $f(x)$ is divided by $(x-2)$ it will remain $5$ and if it's divided by $(x^2-x-6)$ it will remain $(2x+5)$. What is the remainder of the division if $f(x)$ is divided by $(x^2-4)$? My attempt: Let g(x) be the result of the…
user516076
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Sturm sequence - polynomial with only real roots

Let $P_n(x)$ be a sequence of polynomials $\deg P_n= \deg P_{n-1}+1.$ Suppose that $$P_n(x)=((a_nn-b_n)x+b_n)P_{n-1}(x)+x(\alpha_n-\alpha_nx)P'_{n-1}(x)$$ I'm having trouble understanding the following statement: $P_n(x)$ has only real roots if and…
Alex
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What was the Original Need/Purpose for Defining Bernstein Polynomials?

I am interested in learning about the reason as to why Bernstein Polynomials were first defined. After consulting the Wikipedia article on Bernstein Polynomials, these appear to be polynomials that follow a certain pattern: My Question: Does anyone…
stats_noob
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How do I determine A polynomial "P" that has a degree equal or inferior to $3$ that has these properties

$1$ is a root of degree 2 and has a remainder of $6X+2$ when divided by $X^2+1$. I tried writing it as $$P(X)=(X-1)^2(aX+b) + R(X)$$ and $$P(X)=(X^2+1)(cX+d) + 6X+2$$ and couldn't find a solution.
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How to transform a monomial

Let's start with the monomial $x$. The goal is to get to a constant term by differentiation and multiplication with $2x$. For some $n \in \mathbb{N}$, you have an exact number of steps $k = 2n+1$ you have to take to get there. For example, for $n =…
fynsta
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Discriminant as a polynomial

Let $k$ be an algebraically closed field, and let $p(x)\in k[x]$. We can think of a general polynomial $p(x)=a_nx^n+a_{n-1}x^{n-1}+\dots+a_1x+a_0$ as a polynomial $q(x,a_n,a_{n-1},...,a_0)\in k[x,a_n,a_{n-1},...,a_0]$ where $a_i$ here are just…
Or Shahar
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