Questions tagged [relations]

For questions concerning partial orders, equivalence relations, properties of relations (transitive, symmetric, etc), a composition of relations, or anything else concerning a relation on a set.

A relation $R$ on a set $X \times Y$ (sometimes also called a relation between $X$ and $Y$) is any subset of $X\times Y$. So a relation is any set of ordered pairs $(x,y)$ such that $x\in X$ and $y \in Y$. Often we write $x\mathrel R y$ instead of $(x,y)\in R$. Sometimes we say a relation is defined on a single set $X$, but this just means that we're letting the relation $R$ be a subset of $X \times X$.

Here are some examples of relations:

  • For a very abstract example of a relation, take $X = \{1,2,3\}$ and $Y = \{a,b,c,d\}$, and let $R = \{(1,b),(3,c),(3,d),(2,c),(2,d)\}$. This $R$ is a relation on $X \times Y$. Fun fact, there are $2^{12}$ distinct relations you could put on $X \times Y$.

  • A function $f\colon X\to Y$ can be defined as a relation on $X \times Y$. The pairs in $X \times Y$ that are members of the relation are the input-output pairs $(x, f(x))$.

  • A partial order is a relation that mimics the notion of one element being greater/less than the other. An example of a partial order is the relation $\leq$ on $\mathbf{Z} \times \mathbf{Z}$ where for two integers $n$ and $m$ we say $n \leq m$ if $n$ is less than or equal to $m$.

  • Given a set $X$, let $\mathcal{P}(X)$ denote the set of all subsets of $X$. We can define a partial order $\subseteq$ on $\mathcal{P}(X)$ by saying that for two susbsets $A$ and $B$ of $X$, $A \subseteq B$ if $A$ is a subset of $B$.

  • An equivalence relation is a relation that mimics the notion of two things being "equal". For example, on the set $\mathbf{Z}$ of integers let's define the relation $\equiv_{37}$ on $\mathbf{Z}\times \mathbf{Z}$ by saying $a\equiv_{37} b$ if both $a$ and $b$ give the same remainder when divided by $37$. If $a \equiv_{37} b$ we say that $a$ and $b$ are congruent modulo $37$.

  • Let $T$ be the set of all triangles in the plane. An example of an equivalence relation on $T$ is the relation of two triangles being congruent.

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Can someone explain me this statement. "Antisymmetric relation is an equivalence relation".

"Antisymmetric relation is an equivalence relation" Whenever I used to prove this statement I come with a counterexample. Let take A= {1,2,3,4} If R= {(1,1),(2,3),(3,4)} then R is antisymmetric but not equivalent. Can someone explain to me how the…
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Let $R_1 = \{(a,b): a \leq b^2 and \ a,b \in \Bbb R \}$ and $R_2 = \{(a,b): a \leq b^3 and \ a,b \in \Bbb R \}$ be two relations on set of real number

Let $R_1 = \{(a,b): a \leq b^2 and \ a,b \in \Bbb R \}$ and $R_2 = \{(a,b): a \leq b^3 and \ a,b \in \Bbb R \}$ be two relations on set of real numbers. Given that $R_1,R_2$ are not transitive. Please provide me counter examples. I could not…
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What does it mean for (x,y) ∈ Z^2?

Does this mean that x and y can only be square integers? 1, 4, 9 etc. ? The problem I am trying to understand is R = {(x,y) ∈ Z^2 : ∃k ∈ Z x=ky}
Matthew
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Binary relation induced by another binary relation

Let $S$ be any discrete set. Let $\prec$ be a binary relation defined over $S$. I refer to the corresponding partial order set as $\langle S, \prec \rangle$, which, I presume, being one possible standard nomenclature. Now, I would like to formally…
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Is it possible to find the equation that links two sets of numbers?

I have two sets of numbers: $ A = {161, 184, 202}, B = {0.398631, 0.520661, 0.627513} $ Is there a way (other than trial and error) to find the equation that turns set A into set B? The order of the numbers in the sets is correct (i.e., 161 relates…
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Is a nullary relation homogeneous?

An $n$-ary relation is a set of $n$-tuples; inside which a tuple either exists or it doesn't. A nullary relation is a $0$-ary relation, in other words it is a set that either contains the only $0$-tuple or it doesn't. A homogeneous relation is a…
SMMH
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effect of relational inverse operator upon a relation A, B, C

Can someone clarify this for me please: If I have a relation R which is of the form A \mapsto (B \mapsto C) and I use the relational inverse operator on R do I get: (C \mapsto B) \mapsto A) or is it (B \mapsto c) \mapsto A? Thanks.
JMcK
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composition relation of $R^3$

I need verification if my answer is right in this composition of relations problem. If A = {1,2,3} and Let R = {(1,2), (1,3), (2,2), (3,3)} be a relation from set A to set A. What would be the relation of $R^3$? My answer is…
zultz
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How can we prove that transitivity implies quasi-transitivity?

Let $R$ be a complete binary relation on $U$. $R$ is Transitive if for all $x,y,z \in U$, $xRy \land yRz \implies xRz$, Quasi-transitive if for all $x,y,z \in U$, $xPy \land yPz \implies xPz$ Prove that if $R$ is transitive, it is also…
user897073
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conditions for being a relation

is this a relation? does every element in set $A$ need to have an image(one or many) in set b??? [ sorry question might be too simple for most of u guys here but just started learning about relations ]
Meet Lalwani
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Could someone explain what anti-symmetric means with regards to relations?

I understand that what a preorder relation is, and I understand what a symmetric preorder –equivalence relation – is, but I don't quite see the logic behind anti-symmetry? For all the examples I've seen where the relation IS anti-symmetric, it has…
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Let relation $R=\{(1,1), (2,2), (3,3), (1,2), (2,1), (2,3) (3,2)\}$ be defined on $A=\{n:3^n>4^{n-1}\}$. Find type of relation.

Clearly R is a symmetric relation. Now for finding the set A, I don’t know the proper method to do it, but I managed to find $A=\{1,2,3,4\}$ (please let me know how to solve without trial and error) Now, $(4,4)$ isn’t in the relation, so does that…
Aditya
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Prove that a relation is antisymmetric

I am a bit confused about proving that a relation is antisymmetric. $x,y \in R$ and $x \sim y$ if $x=2y$ is the given relation. Antisymmetric holds true I think. Could I make this conclusion? Thanks!
user894189
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Is the graph of $y=y$ everything, nothing, or simply an invalid question?

So here's my reasoning: For any $x$, $y=0x+y$ will simply yield $y$, which would lead me to believe that $y=y$ would produce a horizontal line at, well, $y$... except, since for any $y$ the horizontal line will take at place at said $y$, I'd figure…
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Prove that $a\mathrel{R}b \iff$ **a** is a solution to the equation $X²-2bX+b²=0$ is transitive

Let $\mathrel{R}$ by a relation defined on the set $\mathbb{R}$ $a\mathrel{R}b \iff$ a is a solution to the equation $X²-2bX+b²=0$ How do I prove that it's a transitive relation? Here's what I tried : Let a, b, c in R such that $a\mathrel{R}b$ and…
Cheeze
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