Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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How to prove that chessboard of size $n \times 3$, with even $n$ and $n \geq 10$, has a closed knight's tour with induction?

I am trying to do an exercise on this topic. I have realized that base cases should be $n = 10$ and $n = 12$. Also I realized that I would need to use $(n+4)\times 3$ during my inductive step. But that is pretty much it. I really don't understand…
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Part of an induction question

I might have done or not realize something stupid, but I can't seem to prove the following... Inductive hypothesis Assume $\exists$k$\in$N such that P(k) is true. P(k): $\frac{1 \cdot 3 \cdot 5 \cdot\cdot\cdot (2k - 1)}{2 \cdot 4 \cdot 6…
fossdeep
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Having problem in last step on proving by induction $\sum^{2n}_{i=n+1}\frac{1}{i}=\sum^{2n}_{i=1}\frac{(-1)^{1+i}}{i} $ for $n\ge 1$

The question I am asked is to prove by induction $\sum^{2n}_{i=n+1}\frac{1}{i}=\sum^{2n}_{i=1}\frac{(-1)^{1+i}}{i} $ for $n\ge 1$ its easy to prove this holds for $n =1$ that gives $\frac{1}{2}=\frac{1}{2}$ Now assuming $n$ its true I want to say…
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Proof By Contradiction [?]

There are $n$ islands with $n$ bridges connecting pairs of islands (where $n\ge 2$). Prove that some sequence of distinct bridges forms a loop. __ Since it isn't obvious how to prove it directly I think I'm going to argue by contradiction. But I'm…
user228320
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Why are two base cases needed to prove that $n<2^n$ for all $n\geq 0\,$?

So I understand more than one base case is needed when there is a recurrence relation like the Fibonacci sequence. But I don't understand why two base cases are needed in the below example. Is there somehow a recurrence in the statement or does it…
J_SNSD
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Understanding this proof

I don't know how they come from the step prior to the last to the last. If somebody could explain what happens there, that would be appreciated. Thanks in advance!
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Prove by mathematical induction that $\forall n \in \mathbb{N} : \sum_{k=1}^{2n} \frac{(-1)^{k+1}}{k} = \sum_{k=n+1}^{2n} \frac{1}{k} $

Prove by mathematical induction that: $$\forall n \in \mathbb{N} : \sum_{k=1}^{2n} \frac{(-1)^{k+1}}{k} = \sum_{k=n+1}^{2n} \frac{1}{k} $$ Step 1: Show that the statement is true for $n = 1$: LHS = $$\frac{(-1)^{1+1}}{1} = 1$$ RHS = $$\frac{1}{1} =…
MathInferno
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Proving by induction that $\frac{n(n + 1)(2n + 1)}{6} = 0^2 + 1^2 + 2^2 + 3^2 + ... + n^2$

Note: I am asking this question as a simple introductory question to proofs by induction, to which I will give also my formal answer (which should be correct, if not, please comment) for future visitors of this website. I know that to prove…
user168764
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Proving by induction that $a_n = 2^n - 1$, $\forall n \in N$

Note: I am asking this question because I though my solution is interestingly easy and could solve for others with the same problem. If the solution is not completely correct, or incorrect, please feel free to correct it or improve it. I am sorry if…
user168764
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Tips on constructing a proof by induction.

So right now I'm working on a discrete mathematics course and I've been having a bit of trouble figuring out how to prove certain equations using mathematical induction. I have very little trouble understanding how to use mathematical induction to…
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How to prove $0 < a_n < 1$ by induction

I know $n \in \mathbb{N}$ and... $$ a_n = \begin{cases} 0 & \text{ if } n = 0 \\ a_{n-1}^{2} + \frac{1}{4} & \text{ if } n > 0 \end{cases} $$ Base Case: $$a_1 = a^2_0 + \frac{1}{4}$$ $$a_1 = 0^2 + \frac{1}{4} =…
user168764
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Inequality proof by induction, what to do next in the step

I have to prove that for $n = 1, 2...$ it holds: $2\sqrt{n+1} - 2 < 1 + \frac{1}{\sqrt2} + \frac{1}{\sqrt3} + ... + \frac{1}{\sqrt{n}}$ Base: For $n = 1$ holds, because $2\sqrt{2}-2 < 1$ Step: assume holds for $n_0$. $2\sqrt{n+2} - 2 < 1 +…
Bob
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2(n-1) induction

There are $n$ cities and every pair of cities is connected by exactly one direct one-way road. Now more one-way roads have been added between some cities so that between some pairs of cities there may be two direct roads between them, for example,…
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Prove By Induction (Fibonacci Sequence)

Prove by PMI $\gcd(f_n,f_{n+1}) = 1$ for all natural numbers $n$. $f_n$ represents the Fibonacci sequence.
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Proof by induction regarding maximum number of questions one can ask.

sorry for the pretty ambiguous title. It's otherwise hard to describe this problem without stating it in full. There are $n$ points drawn on a whiteboard. Between every pair of points $X$ and $Y$ there are drawn either an arrow from $X$ to $Y$, from…
user176049