Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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Prove that $2^k > k^3 $ for all $k\ge10$

I've no clue how to go ahead with this, all I know is it will be solved with induction. Proved it's true for $k=10$ Assumed it's true for $k$ Need to prove that $2^{k+1} > ({k+1})^3$ Any pointers? I'm struggling with tough Induction questions so…
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Proof by induction of the inequality

I got problems trying to prove the following inequality by the induction method $1+ \frac{1}{2^2}+ \ldots + \frac{1}{n^2} < \frac{7}{4}$ I've found a similar example with 2 in the right and it was recommended to prove a stronger statement, which…
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Proof that every integer > 3 cash amount can be payed by arbitrary number of coins of value 2 and 5

This question is about the following word problem: Show that every integer cash amount $k$ greater than 3 can be payed by $m$ coins of value 2 and $n$ coins of value 5. where: $ m, n \in \mathbb{N}_0, $ I tried to prove this by induction. So for…
Ymeris
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Mathematical Induction: Stamps

Possible Duplicate: Representing Any $n \geq 4$ as a Sum of 2’s and 5’s Show that if you have enough three cent and four cent stamps then you can make any postage greater than six cents. How would I prove this by induction?
DaveHkl
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If $m < n$, then $k^m < k^n$?

For natural numbers, I would like to prove that if $m < n$, then $k^m < k^n$ for $k$ not $0$ or $1$. Induction seems viable, but I don't know which variable to induct on. Any suggestions?
user7709
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Use induction: postage $\ge 64$ cents can be obtained using $5$ and $17$ cent stamps.

I have come up with: Assume for any $n\ge 64$ there exists numbers $x$ and $y$ such that $n = 17x + 5y$ and also then that $n+1 = 17x + 5y + 1$ but am fairly new to the concept of induction and not sure where to go after this.
Derpm
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Mathematical Induction with tan extremely hard

Extremely hard high school mathematical induction question. Part i is easy. Part ii not so sure but I'm not sure how to get rid of the pi/2 when tan pi/2 is non existent. I think multiplying that given equation by 2 may work? and then creating…
D.Ronald
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Double inducton: Addition is commutative

I want to show using double inducton that the addition is commutative: For $m,n\in \mathbb{N}$ it holds that $m+n=n+m$. I have done the following: For each $n\in \mathbb{N}$ let $E_n$ be the proposition: $\forall m\in \mathbb{N}: m+n=n+m$. Base…
Mary Star
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How to prove simples statements with induction.

For each $n \in \mathbb{N}$ we have a statement $P(n)$. We know that the following statements are true: $$P(0) \tag1$$ $$P(1)\tag 2$$ $$\forall n\in \mathbb{N} (P(n)\text{ and }P(n+1)) \to P(n+2) \tag3$$ I'm to show that $\forall k\in \mathbb{N}$…
Mathaniel
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Induction: How to prove propositions with universal quantifiers?

In my book, they prove with mathematical induction propositions with successions like this: $$1 + 3 + 5 + \cdots + (2n-1) = n^2$$ In all exercises. However, recently I took some exercises from a different paper and instead of these it told me to…
Saturn
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Proving a bijection with contradiction and induction

Let $A = \{a_1, a_2, . . . , a_n\}$ where $a_1 < a_2 < \cdots < a_n.$ Let $\phi : A \to A$ be one-to-one correspondence, and $a_1 + \phi(a_1) < a_2 + \phi(a_2) < \cdots< a_n + \phi(a_n).$ Show that $\phi(a_i) = a_i$ for $i = 1, 2,\ldots , n.$ We…
dcxt
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How to prove by induction that for $n$ $ \in \mathbb N $ , $ 2 n - 18 < n^2-8n +8 $?

Question: Prove for $n$ $ \in \mathbb N $ , $ 2 n\ -\ 18\ <\ n^2-8n\ +8 $ My attempt: $ Base\ Case:\ n\ =\ 1,\ it\ holds. $ $I.H:\ Suppose\ 2k-18\ <\ k^2-8k+8,\ where\ k\ is\ a\ natural\ number.$ $ Then,\ \left(k+1\right)^2-8\left(k+1\right)+8\ =\…
user444945
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Prove $n2^n < n!$ for $n \geq 6$

So far I have this: Let P(n) be the statement "$n2^n \lt n!$". $k_{0}=6$. $(6)2^6 = 384 <720=6!$. $P(k_{0})$ is true. Let $n \geq 6$ and assume P(n) to be true. By the induction hypothesis, $(n+1)2^{n+1}=(n+1)(2)2^n ...$ Somehow this gets to be…
AdamK
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Formally, why can we start induction in any base case?

I'm taking a course in Set Theory, and I want to prove that finite product of $\omega$ has cardinality $\omega$. I already have that $P(\omega \times \omega) = \omega$. So I can say that using ordinary induction we have that for any $n \in \omega$…
HeMan
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Show that all horses are of the same color.

Im trying to understand the solution about this, and all the other solutions are.. a bit weird for me and dont answer all my questions! Reference : Questions on "All Horse are the Same Color" Proof by Complete Induction Im using the answer there as…
user365485