Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

10150 questions
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Constructive Mathematical induction

$r_n = 2r_{n-1} + 5r_{n-2}$ Where $r_1 = r_2= 2$, Assume $r_n \le ab^n$ (primarily upper bound b as tightly as possible, and secondarily upper bound a as tightly as possible. Use Constructive Mathematical induction to derive an upper bound for…
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Prove $2^n$ is smaller than binomial coefficent of $2n$ over $n$

I need to show that $\binom{2n}{n} \geq 2^n$. I'm required to do this by using induction. For $n=1$ this is rather easy. I just don't get very far when going to the next step for $n+1$. Is there a way to write this as a sum, or is there another…
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How to solve this with mathematical induction?

$$\sum_{i=0}^n \frac{i}{2^i} = 2 - \frac{n+2}{2^n} $$ Let's skip the check, since when n = 1, I have $\frac{1}{2} = \frac{1}{2}$ What i will next do ? What for expression i may receive ? $$\sum_{i=0}^{n+1}\frac{i}{2^i} = 2 - \frac{n+2}{2^n} $$ My…
Boujozo
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Sum the first n^3 how provide with using mathematical induction?

I having next formula and need solving with helps mathematical induction. $\sum_{i=1}^n i^3 = \biggl(\frac{n(n+1)}{2}\biggl)^2$ My next steps in solving the task: a)I check the validity of this assertion for n = 1 $\sum_{i=1}^1 1^3 =…
Boujozo
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Bounded recursive sequence - Proof by induction

Given the sequence $(x_n)$ defined by \begin{cases} x_1 &= 1\\ x_{n+1} &= \frac{1}{2}\left(x_n + \frac{2}{x_n}\right), \end{cases} prove that $1 \leq x_n \leq \frac{3}{2}, \forall n \in N$. I verified the base case for $n=1$ and $n=2$. Assumed…
KirkLand
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prove that exactly one player has a winning strategy - version of nim game

Game Description : the game is between 2 players and start with a pile of 'n' balls and A = {a1,a2,...,ak} ⊆ {1,....,n} . Course of the game : each player, in his turn, picks a ∈ A balls from the pile. the loosing player : the player that can't play…
Liavba
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Deduce that the next integer greater than $(3+\sqrt{5})^n$ is divisible by $2^n$

I can prove it for base case $n=1$. I have assumed it true for $n=k$ But I cant prove it for $n=k+1$.
user659479
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mathematical induction methods

Mathematical induction I know there is one specific way of proving it which is say for instance the example: Method 1 Prove using mathematical induction that: $$2^n>n+4, n\ge 3$$ I will skip straight to the induction step: We assume $P(k)$ is true…
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Prove the following theorem with induction

Prove by induction that if $n$ is a natural number and $x, y, z$ are real numbers such that $|x| \leq z$ and $|y| \leq z$ then $$|x^n −y^n | \leq nz^{n−1}|x−y|.$$ I need to be able to solve this without using any forms of derivatives, though it is…
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Prove that $\sum_{i=1}^{n} i \times i! = (n+1)! - 1$ by induction

\begin{align*} \sum_{i = 1}^{k + 1} i(i!) & = \sum_{i = 1}^{k} i(i!) + (k + 1)(k + 1)!\\ & = (k + 1)! - 1 + (k + 1)(k + 1)! & \text{by the induction hypothesis}\\ & = (1 + k + 1)(k + 1)! - 1\\ …
Evan Kim
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Prove that $m \equiv S_m \pmod 3$?

I'm not very fluent in mathematical proofs. High School has, sadly, not taught me any kind of proof-theory. That's why I would like your help with my proof of $$m \equiv S_m \pmod 3.$$ where $S_m$ is the digit sum of $m$ and $\wedge$ is a…
IAE
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Stones game proof by induction

I'm struggling with proof by induction for the following game Two players called P2 and P2 are playing a game with a starting number of stones. Player always plays first, and the two players move in alternating turns. The game's rules are as…
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finding general law given a few statements

I am doing a problem on induction and the first step is to guess the general law of the following statements: $1=1$ $1-4=-(1+2)$ $1-4+9=1+2+3$ For the LHS i got that we are summing $(-1)^{r+1}*r^2$ from $r=1$ to $n$ but i am quite stuck on the…
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$2^{2n+1} +1$ divisible by $3$

$2^{2n+1} +1$ divisible by $3$ Inducción over n Let $n=1$, then: $$2^{2(1)+1}+1=2^{3}+1=9$$ It works! Hip. $$2^{2n+1} +1=3k$$ Then we have to show: $$2^{2n+3} +1=3k$$ Any guess?
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Prove $a^{n}*a^{m}=a^{n+m}$

$a^{n}*a^{m}=a^{n+m}$ Induccion over $a$ Being $a=0$ $$0^{n}*0^{m}=0^{n+m}$$ $$0*0=0$$ it works! Hip. $$a^{n}*a^{m}=a^{n+m}$$ Now let $S(n)$ be the succesor of $n$ We have to show the following: $$S(a)^{n}*S(a)^{m}=S(a)^{n+m}$$ I been trying to…