Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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$1 + \frac{1}{\sqrt{2}} + \frac{1}{\sqrt{3}} + \ldots + \frac{1}{\sqrt{n}} \leq 2\sqrt{n}$ by mathematical induction

I need the following by the principle of Mathematical induction: \begin{align*} 1 + \frac{1}{\sqrt{2}} + \frac{1}{\sqrt{3}} + \ldots + \frac{1}{\sqrt{n}} \leq 2\sqrt{n} \end{align*} I can easily find out the base case for n=1 is true. However, I…
user702450
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For which $n,~~ 2^n>n^3~$ is true?

For which $n,~~ 2^n>n^3~$ is true ? It’s my school homework) I realized that I need to use induction for this task. The base would be $n=10~~ (n=1~$ also works$)$. I can’t really figure out the rest(.
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induction proof question - not getting right answer

Prove: 4 + 10 + 16 + ... + (6n -2) = n(3n + 1) So this is my working out but my final answer shows that they don't equal ...but it should right? I can't see where I've gone wrong.
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Prove by induction that the $n$th iterate of $\frac{x}{\sqrt{1+x^2}}$ is $\frac{x}{\sqrt{1+nx^2}}$

If $f(x)=\frac{x}{\sqrt{1+x^2}}$ prove by mathematical induction that $f(f(...f(x)...))$ = $\frac{x}{\sqrt{1+nx^2}}$. (Noting that there are n $f$'s in the LHS) I have no idea where to start with this one. Which method is best suited for proving…
Brown
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How can I prove this statement by mathematical induction?

I'm having trouble proving that $$n! \leqslant n^n \, \, \, \,\forall \,n \in \mathbb{Z}^+$$ by mathematical induction. I checked if it worked for $n = 1$ and then supposed that it worked for $n$, to then prove if it worked for $n+1$. In this last…
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Find all natural numbers n so that $ n^3 +(n+1)^3 >(n+2)^3$

Find all natural numbers n so that $$ n^3 +(n+1)^3 >(n+2)^3$$ I have to do induction to prove this. I expanded and simplified both sides, am I on the right track? I don't know what to do from here
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some induction prove question.

how to prove that $\forall n \in \mathbb{N^+}, \forall p \in \mathbb{P} ,\forall a \in \mathbb{(N^+)^n}, p|(\prod^n_{i=1} a_i) \Rightarrow (\exists k \in {1,2,3,\ldots,n }, p|a_k)$ ? PS:$\Bbb{P}$ is prime number.
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Flowchart as a solution to a word problem

Here is the word problem: There is a tournament where teams compete against each other exactly once, and determine the winner. Show that the teams can be lined up in such an order, that each won against its immediate neighbor on the right side. My…
Leo
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Principle of mathematical induction, negative numbers

I know mathematical induction works for negative numbers. But, why it is giving me inappropriate results here? Consider $1+2+3+\dots+n=\frac{n(n+1)}{2}$. I could prove base case by taking $n=0$. Then, after I suppose it holds for $K$, some integer,…
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proof by mathematical induction n!< n^n

"Let P(n) be the statement that (n)! < (n)^n, where is an integer greater than 1. Prove by mathematical induction that P(n) is true for all integers n greater than 1." I've written Basic step Show that P(2) is true: 2! < (2)^2 1*2 < 2*2 2 < 4…
Mampenda
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I'm actually lost regarding inductions

Basically, it's what it says in the title, could someone solve step by step this induction? It would be even better with an expanation for said steps, but it's not all that needed, I want to read the solution mostly to decipher how to solve it,…
Hareka
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Prove by induction: $b^n-a^n=(b-a)\cdot \sum_{k=0}^{n-1}{a^k\cdot b^{n-1-k}}$ $\forall n\in \mathbb{N}$ and $a,b\in \mathbb{R}$

Prove by induction: $b^n-a^n=(b-a)\cdot \sum_{k=0}^{n-1}{a^k\cdot b^{n-1-k}}$ $\forall n\in \mathbb{N}$ and $a,b\in \mathbb{R}$ $\exists n\in \mathbb{N}:b^n-a^n=(b-a)\cdot \sum_{k=0}^{n-1}{a^k\cdot b^{n-1-k}}$ $\Rightarrow b^{n+1}-a^{n+1}=(b-a)\cdot…
user666536
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Induction/More so A question about simplifying square roots

Ok I Get everything up until the point where it says. k $\sqrt{k+1}$ + $\sqrt{k+1}$ = (k+1) $\sqrt{k+1}$ How in the world did they get there? Or am I missing something else
Dani Jo
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Prove by induction that $\frac{d^ny}{dx^n} = n3^{n-1}e^{3x}+x3^ne^{3x}$ for the equation $y(x)=xe^{3x}$

I have been solving this question, and I proved n=1, assumed n=k is correct and attempted to solve n=k+1. I got to the point where $$\frac{(d^{k+1}y)}{dx^{k+1}} = \frac{d⋅d^ky}{dx⋅dx^k}$$. Although I got this, I don't know how I can combine the n=k…
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Proof that an even number plus an odd number is equals to an odd number

How can I prove using an induction technique that an even number plus an odd number is always equals to an odd number? Thanks in advance!