Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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Mathematical Induction for $n \geq 1$

I want to prove, using mathematical induction, the following proposition: $$1+\frac{1}{\sqrt{2}}+...+\frac{1}{\sqrt{n}}\:\ge \sqrt{n}, \forall n \geq 1 \in \mathbb{N}$$ My thesis is: $$\frac{1}{\sqrt{n}}+\frac{1}{\sqrt{n+1}}\ge \sqrt{n+1}, \forall n…
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Basic mathematical induction question.

Prove using induction: For any natural number $n$ there is a natural number $m$ such that $n\le m^2\le 2n$. Obviously letting $n$ and $m$ equal $1$ satisfies the first part of mathematical induction. I'm stuck at the second part. I believe we…
Zoey
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Fibonacci sequence for any $n \in \mathbb N$ $F(2n) = \sum_{i=1}^{n} F(2i - 1)$

Fib sequence is below \begin{cases} 0 & n = 0 \\ 1 & n = 1 \\ F(n-1) + F(n-2) & n > 1 \end{cases} for any $n \in \mathbb N$, $F(2n) = \sum_{i=1}^{n} F(2i - 1)$ for $n \geq 1$ I'll prove this using induction Base Case: Let n =…
Tinler
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Simple Mathematical(+1-1 ?)

I've been trying to prove using mathematical induction the following statement : "Prove that for all integers n ≥ 1 we have 8|9^n − 1 ." What I did and where I struggled : Verify : if n=1 9^1 -1 = 8 TRUE Assumption : 9^n -1 = 8m 9^(n+1) - 1…
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Induction on string

suppose $\theta$ is a function using only the binary connectives "and" and "or" and a single propositional variable $p$. Show by induction on length of $\theta$ that the formula $p \implies \theta$ is a tautology I know for basic step that $n=0$ and…
ABUG
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Proving recurrence function with sigma notation?

Btw zero is a natural number in this case. I'm confused on how to handle the sigma in the inductive step, oh and im just trying to prove $f_2(n) = 2^n$ so ignore the second half. My attempt: Prove $P(n): f_2(n) = 2^n, \forall n \in \mathbb N$ I'll…
Tinler
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Induction problem with sum to n-1

I am having trouble solving this induction problem because when I do the last step proving P(n+1), I do not know what exactly I need to substitute. Note that in the expression below k is a positive integer number. $\displaystyle\sum_{i=0}^{n-1}…
user415285
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Prove by induction that for $n\geq1$, $(a_1+a_2+...+a_n)/n \geq (a_1*a_2*...*a_n)^{1/n}$

Prove by induction that for $n\geq1$, $(a_1+a_2+...+a_n)/n \geq (a_1*a_2*...*a_n)^{1/n}.$ I proved the base case, not sure how to do the inductive step. The values of the sequence are greater than or equal to zero.
Jack Pan
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Prove Bernoulli's inequality

Using the proposition I have checked it for a($1$) $1+x=1+x$ so a($1$) is true A($n$)=$(1+x)^n\ge 1+nx$ assuming this is right according to inductive hypothesis Considering a($n+1$) $( 1+x)^n+1\ge 1+(n+1)x$....($1$) Now $(1+x)^n+1\ge…
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Induction Proof:

I am stuck on this problem. I understand the fundamentals of induction proofs, but I am unfamiliar with induction on two variables. Here's the prompt: Prove that for every positive integer $k$, the following is true: For every real number $r > 0$,…
SomeK1d
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need to prove by induction

Let () be defined recursively as follows: $(1) = $, and $(n) = (/) + $, $\forall \geq 2$ where $, $, and $$ are positive constants, $ \not= 1$, $$ is an arbitrary constant, and $ = $ for some non-negative integer $$. Prove by induction on $k$ that…
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Prove by induction that $1\cdot2+3\cdot4+\cdots+(2n−1)\cdot 2n=n(n+1)(4n−1)/3$

Prove by mathematical induction that $$1\cdot2+3\cdot4+\cdots+(2n−1)\cdot2n=n(n+1)(4n−1)/3$$ for all $n\in\mathbb{N}$. Let claim (n) be $$(1\cdot 2) + (3\cdot4) +\cdots+(2n-1)\cdot2n = n(n+1)(4n-1)/3$$ claim(1):…
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Finding right value for formula and proving it

I need to find the p value for which every n: $n \ge p$ and $n \in \mathbb{N}$ I am given: $n! \ge 2^n$ I'm really not sure how to approach this question. Say my base proof is $p=4$ so $n \ge 4$ and then I tried: $(n+1)! \ge 2^n \times 2^1$ (what…
bm1125
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Loaded Induction Hypothesis

Could anyone please explain me what is Loaded Induction Hypothesis and its difference from a standard one? I imagine that it must be a stronger hypothesis in some way.
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Prove by induction: $\frac{1}{2}+\frac{1}{4}+ \frac{1}{8}+ ... +\frac{1}{2^n} < 1$

Prove by induction: for all $n > 1$ $$\frac{1}{2}+ \frac{1}{4}+ \frac{1}{8}+ ... + \frac{1}{2^n} < 1$$