Questions tagged [logarithms]

Questions related to real and complex logarithms.

The logarithm is generally defined to be an inverse function for the exponential. If $x > 0$ is a real number and $b > 0$, $b \ne 1$, then the base-$b$ logarithm is defined by

$$\log_b(x) = y \iff b^y = x$$

The most commonly used bases are base $10$ and $2$ (which frequently arises in computer science), and particularly base $e$. The natural logarithm $\ln$ is defined to be $\log_e$.

Alternatively, the natural logarithm can be defined to be a primitive of the function $$f(t) = \frac{1}{t}$$ subject to the condition that $\ln{1} = 0$.

In the study of complex numbers, the solutions $a$ of $e^{a} = z$ are called complex logarithms. This uniquely specifies the modulus of $a$, but not its argument; as such, we define the principal logarithm $\operatorname{Log}(re^{i\theta}) = \ln{r} + i \theta$, with the restriction $-\pi < \theta \le \pi$ (or alternatively, $0 \le \theta < 2\pi$). This leads to a branch cut, or discontinuity - alternatively, the complex logarithm can be viewed as a multi-valued function.

Reference: Logarithm.

This tag often goes along with .

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Upperbound this difference between two log expressions

I have the difference between the following log expressions and I am trying to bound the difference, $$F= \log \left(1+ \left(2+\frac{1}{\sqrt{2}}\right)^2 x^2\right) - \log \left(1+ \left(1-\frac{1}{\sqrt{2}}\right)^2 x^2\right) $$ Can I say…
Henry
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Must square root of $e$ be positive?

I have always thought that there is two solutions to the square root of a real number, one being positive and the other being negative. However, in Penrose's book, A Road to Reality, he seems to claim that $e^{1/2}$ will always give a positive…
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Logarithm - Convert to exponential form

this needs to be converted to exponential form and I can't seem to figure it out. Any help is appreciated, thank you! $$10 \log(1+i) = \log 2$$
Ryan
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Is it correct to say that $\log_2 0=-\infty$?

The logarithm is not defined at $x=0$, because it tends to $-\infty$ as x tends to 0 from above. But is it nevetheless correct to say that $$ \log_2(0)=-\infty? $$ Or is it better to say/ write $$ \log_2(0)=\lim_{x\downarrow 0}\log_2(x)=-\infty $$
mathfemi
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Logarithmic property justification

I saw this particular line slammed in a proof and it bothers me I can't understand why this is obvious and how would one justify this : $$ 7^{\log (n)} = n^{\log (7)} $$ Can anyone explain ?
hutcher
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Name of Logarithmic Curve

I was playing with the Desmos graphing calculator and "discovered" the following curve $(\ln x)^2 + (\ln y)^2 = 1$ (I originally found it in the parametric form $(e^{\cos t}, e^{\sin t})$). It would seem to be the equivalent of a circle on a log-log…
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Show that $\ln(1+x)=\ln x+\frac{1}{x}-\frac{1}{2x^2}+\frac{1}{3x^3}-\frac{1}{4x^4}+\cdots$ when $x>1$

If $x>1$ show that $\ln(1+x)=\ln x+\frac{1}{x}-\frac{1}{2x^2}+\frac{1}{3x^3}-\frac{1}{4x^4}+\cdots$ I know from binomial expansion that $(1+x)$ will produce a divergent series in the form of $1-x+x^2-x^3+\cdots$ but I don't know how to apply that…
hohner
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Rate of decay with half life, present grams and future grams

The half-life of silicon-32 is 710 years. If 80 grams is present now, how much will be present ijn 200 years? I used A(t)=Ae^kt to solve for the rate (k). A(710)=1/2Ae^k(710) 1/2A=Ae^k(710) 1/2=e^k(710) ln1/2=k710 ln1/2/710=k k= And this is where…
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Why can we take the log of both sides?

I was watching a video that proves the "Log of a power" rule. I'm just having trouble understanding the loga(a^x) = x rule - which he uses in the proof And I don't get why you can log both sides. I know whatever you do to one side of a equation…
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solve $\log_3^2(x)-\log_2(x)=2$

The solution for the equation $\log_3^2(x)-\log_3(x)=2$ is a) $s=\{2,-1\}$; b) $s=\{6,-3\}$; c) $s=\{9, 1/3 \}$; d) $s=\{27, 1/9 \}$; e) $s=\{ 1/6 ,12\}$ It was given in a test at school and I could not solve. I put on wolfram and the answer is not…
Matthew
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Comparing numbers in form $x^y$

Let's consider two numbers in form $x_1^{y_1}$ and $x_2^{y_2}$ How can we compare those two numbers without evaluating them ? Can we use logarithms to check it ? If yes - how ? Thanks in advance. P.S It's not my homework :)
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Solving for $x$ using exponential log laws

For $\log_2(x) + 2\log_2(x-1) = 2 + \log_2(2x+1)$ I moved all the $x$ to left side, used got rid of log and got $x-(x-1)^2 - (x+1) = 4$ Simplyifing I get $x^2-2x=4$ The answer should be $x = 4$ (I checked on wolfram alpha) Help please?
Kieran
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How to solve this logarithmic equation whose expressions have different bases?

I have been trying to solve the following equation for a while and i can't seem to figure it out, your help would be greatly appreciated. Here is the equation: $3^x$=$5^{x-1}$
FutureSci
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Find the range of values that $x$ can take if $9 \log_x5 = \log_5x$

I'm stuck on a homework question about logarithms. I can't work out how to do it, and all I've managed to do is turn $9 \log_x5$ into $ \log_x5^9$. Can anyone guide me onto the right path to solve this?
imulsion
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Simplifying / Solving for $x$

I'm new here, looking for some help please. I've been at this question for 4+ hours, not getting anywhere, haha. $\log_2 (kx) = a$ Question asks to solve for $x$ So far my best try is $\log_2 x + \log_2 k = a $ $\log_2 x = a / \log_2 k$ ~~~ I feel…