Questions tagged [logarithms]

Questions related to real and complex logarithms.

The logarithm is generally defined to be an inverse function for the exponential. If $x > 0$ is a real number and $b > 0$, $b \ne 1$, then the base-$b$ logarithm is defined by

$$\log_b(x) = y \iff b^y = x$$

The most commonly used bases are base $10$ and $2$ (which frequently arises in computer science), and particularly base $e$. The natural logarithm $\ln$ is defined to be $\log_e$.

Alternatively, the natural logarithm can be defined to be a primitive of the function $$f(t) = \frac{1}{t}$$ subject to the condition that $\ln{1} = 0$.

In the study of complex numbers, the solutions $a$ of $e^{a} = z$ are called complex logarithms. This uniquely specifies the modulus of $a$, but not its argument; as such, we define the principal logarithm $\operatorname{Log}(re^{i\theta}) = \ln{r} + i \theta$, with the restriction $-\pi < \theta \le \pi$ (or alternatively, $0 \le \theta < 2\pi$). This leads to a branch cut, or discontinuity - alternatively, the complex logarithm can be viewed as a multi-valued function.

Reference: Logarithm.

This tag often goes along with .

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Logarithmic inequality

Solve the inequality: $$ \log_8(x^2-4x+3) < 1 $$ $$ \log_8(x^2-4x+3) < \log_8(8) $$ $$ \log_8(x^2-4x+3) - \log_8(8) <0 $$ $$ \log_8 [(x^2-4x+3)/8] < 0 $$ Thats what I did for the question so far... and I'm confused as to what to do next. Can someone…
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Checking a possible logarithm identity: $(\sqrt{2})^{\lg n} \stackrel{?}{=} 2^{\sqrt{2\lg n}}$

I have to check if $(\sqrt{2})^{\lg n} = 2^{\sqrt{2\lg n}}$. My idea was to take logs: $\lg\ (\sqrt{2})^{\lg n} =\lg(2^{\sqrt{2\lg n}})$. But how to simplify further? What should I do next? Please, explain in details if possible.
Bob
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What log rule was used to simply this expression?

I'm unclear how the left side is equal to the right side. $$365\log(365) - 365 - 305\log(305) + 305 - 60\log(365) = 305\log\left(\frac{365}{305}\right)-60$$ I know $\log(a) - \log(b) = \log (a/b)$ but if you stick constants before each ln() then…
user1068636
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solve for $x$ without using softwares $\log_{\sqrt{x}}2+\log_6x^x=4$

Is there any nice way to solve this equation without wolfram? $\log_{\sqrt{x}}2+\log_6x^x=4$ Thanks.
dave
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It's on Indefinite Integrals

$$\int \sqrt{ 1 + 2 \tan x ( \tan x + \sec x )} dx$$ Please tell me the way of solving such questions. like what could i assume sec x or sec x tan x to be equal to?
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Common logarithm question

I'm studying logarithms and am doing an exercise where you're supposed to evaluate the solutions of common logarithms without using a calculator. I'm very stuck on this one particular question. I know the answer because I used my calculator, but I'd…
imulsion
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Any idea how to solve this equation?

Any idea how to solve this equation? $$x^2\log_{3}x^2-(2x^2+3)\log_{9}(2x+3)=3\log_{3}\frac{x}{2x+3}$$
Chun-Yue
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Solving ln/exponent question

How do I change the subject of the equation from x to y in the following equation: $$x=[4.105-\ln(\sqrt{y})]^2$$
ADGB
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Logarithms equation, litteral

I have problems with the following logarimthic equation: $$\log _a \left(\frac{x+\sqrt{x^2+5}}{5}\right) = b$$ How can I compute $ \log _a (x-\sqrt{x^2-5})$ in terms of $b$?
Siscia
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Find the value of the Logarithmic Expression

Why is $\log_6 1$ equal to $0$ ?
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Why does the same inequality give different answers?

$\left(\log _2\left(x\right)-2\right)\left(\log _2\left(x\right)+1\right)<0$ has a solution $\frac{1}{2}
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Find $\log_{p}X^2$?

Given that $\log_{p}X=5$ and $\log_{p}Y=2$, find i) $\log_{p}X^2$ I did this, $X=p^5$ and $Y=p^2$ But how do I use them? Should I find $p$?
Kiara
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Is $\lg_{\frac{2}{3}}{\frac{1}{n}} = \lg_{1.5}{n}$

I am asking another question at StackOverflow about Big-O On 1st line is something like The size of the problem at level k is (2/3)kn. The size at the lowest level is 1, so setting (2/3)kn = 1, the depth is k = log1.5 n (divide both sides by…
Jiew Meng
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Canceling out log2

How would go about cancelling out the $\log_2$. Is it possible for the TI 89 to handle this? I'm not sure how to put $\log_2$ in my TI 89. $20=30\cdot \log_2(1+x)$
cokedude
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Struggling with a Form of Logarithm question during my revision

I am doing AS Mathematics In the UK under the examining board edexcel. I came across this question in a List of exam questions given to me by my teacher However I can't work out how to do it. $$2^x 4^{x+1} = 8$$ Now I understand that $4^{x+1}$ is…
Qinusty
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