Questions tagged [logarithms]

Questions related to real and complex logarithms.

The logarithm is generally defined to be an inverse function for the exponential. If $x > 0$ is a real number and $b > 0$, $b \ne 1$, then the base-$b$ logarithm is defined by

$$\log_b(x) = y \iff b^y = x$$

The most commonly used bases are base $10$ and $2$ (which frequently arises in computer science), and particularly base $e$. The natural logarithm $\ln$ is defined to be $\log_e$.

Alternatively, the natural logarithm can be defined to be a primitive of the function $$f(t) = \frac{1}{t}$$ subject to the condition that $\ln{1} = 0$.

In the study of complex numbers, the solutions $a$ of $e^{a} = z$ are called complex logarithms. This uniquely specifies the modulus of $a$, but not its argument; as such, we define the principal logarithm $\operatorname{Log}(re^{i\theta}) = \ln{r} + i \theta$, with the restriction $-\pi < \theta \le \pi$ (or alternatively, $0 \le \theta < 2\pi$). This leads to a branch cut, or discontinuity - alternatively, the complex logarithm can be viewed as a multi-valued function.

Reference: Logarithm.

This tag often goes along with .

10168 questions
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Finding unknown in log equation

I was given a log equation: $$D = 10 \log (I/I_0) $$ $I$ is the unknown in this case, $I_0 = 10^{-12}$ and $D = 89.3$. I did the following steps: $$ \begin{aligned} \ 89.3 &= 10 \log \left(\frac{I}{10^{-12}}\right) \\ \ \frac{89.3}{10} &= \log…
jn025
  • 989
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How to find the highest possible value and time to achieve it with a set increment and percentage decrease plus rounding?

I'm trying to answer a preparation question in math, but I don't get it, so an formula with an explanation would be very helpful! In a simple system measuring recent user activity each user have one personal counter. This counter increases by one…
Jack
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Anti-log of a number

If we accept both positive and negative values for the square root of a number, then can the anti-log of a number be negative?
Yashbhatt
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Solving log equations

I had the problem of expressing $log_9(y)=\frac{x+4}{2}$ in the form $y=k.a^x$. I got this far: $2log_9(\frac{y}{81})=x$ and was wondering if it is valid to draw the conclusion that $\frac{y}{81}=2(9^x)$, whichwould make $k=162$ and $a=9$.
user148298
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I need help with Expanding logs

I know the log rules for expanding but I am not sure how to expand these difficult ones: (also the x's here depending upon the context are multiplication) $$\log_4(x^4yz)^2$$ $$\log_3 (((6\times 5)^2)/11)^2$$ $$\log_2(d \sqrt[3]{abc})$$ $$\log…
Trent
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Simplyfing Log Question

Don't know the concepts of diving and multiplying whole logs. $\frac{\log _a\left(x\right)}{\log _a\left(y\right)}\cdot \frac{\log _b\left(y\right)}{\log _b\left(x\right)}$ Can you please tell me how to simplify this?
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inverse function of $y=ax\ln(bx)$

let be the function $y=ax\log(bx)$, here $a$ and $b$ are constants and $\log$ is the natural logarithm how can i evaluate the inverse function of this in terms of the Lambert $W$-function ??
Jose Garcia
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Evaluate the log expression

Evaulate : $$ \frac{1}{\log_{xy} (xyz)} + \frac{1}{\log_{yz} (xyz)} + \frac{1}{\log_{zx} (xyz)} $$ I think that the following property of log will be used: $$ \log_a (b) * \log_b (c) * log_c (a) = 1 $$ But I don't know how?
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Why $x-\ln (1+e^x)=c$ has a solution for every $c<0$ and not otherwise?

The equation $x-\ln (1+e^x)=c$ has a solution for every $c<0.$ Why is that restriction needed? Why are not we allowed to take positive $c$? I can see that $c=0$ is impossible as $x=\ln (1+e^x)$ means $e^x=1+e^x$ or $'0=1'.$
Silent
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I can't find second solution to this logarithmic problem!

I kind of got stuck on one step in solving a logarithmic equation. The equation given was: x^3lnx - 4xlnx = 0 My steps so far: x^3lnx - 4xlnx = 0 ln((x^x^3)/(x^4x)) = 0 e^ln((x^x^3)/(x^4x)) = e^0 (x^x^3)/(x^4x) = 1 x^x^3 = x^4x now I would just…
Juraj
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Name for property?

This may be a stupid question, it may not. But I was working on some basic logarithm problems and found out that: $-\log(a/b)=\log(b/a)$ Is there a name for this property? Here's my…
user16795
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A question on Logarithms

Q: Given that $\log_3(x) = a$ solve for $x$, $\log_3(9x) + \log_3(\frac{x^3}{81}) = 3$ \I make progress by writing $\log_3(9x) = 3^{2+a}$ and $\log_3(\frac{x^3}{81}) = 5a - 4$. However, I can't finish it off. Thanks
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Equation in Logarithm

We have ${\log_45} = a $ ${\log_56}= b $ and we have to find ${\log_32} $. I tried the question but because of the different bases I was not able to get the solution.
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Help with logarithmic equation?

Find the value of x if: $(2^x)^2 + 3(2^x) - 18 = 0$ So far, I have done $(2^x)^2 + 2^x(3)=18$ $(2^x)^2+2^x=6$ What should i do with $(2^x)^2+2^x$ so i can have only one $^X$ on the left side of the equation?
Helena
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Help with logarithms?

Find the value of $x$ in: $5.25 = -\log_{10} (x)$ What should I do with a negative log? Should i do $5.25= \frac{1}{\log_{10}(x)}$ ?
Helena
  • 105