Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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Prove $2^{(n+1)}>n^2$ by induction

Prove $2^{(n+1)}>n^2$, for all $n \in \mathbb{N}$. I started by verifying the condition for $1$. $$P(1):2^{1+1}>1^2$$ $$P(1):4>1$$ That is true. Then I supposed $P(k)$ true, for some $k \in \mathbb{N}$. Now I've to prove…
user24047
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Basic Proof By Induction, Assistance Required

With the following question. Is it better to start the proof by proving it for n=0, n=1 or both? Once I've done that, I prove it for n=p where p is any integer equal to or greater than 0. For the third part I prove it for n=p+1. It's easier to…
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Trouble understanding induction on two integer variables

I am trying to understand induction on two integer variables Induction on two integer variables Let's take this case: $P(0,0)$ $\forall x,y. P(x,y) \Rightarrow P(x+1,y)$ $\forall x,y. P(x,y) \Rightarrow P(x,y+1)$ $\forall x,y. P(x,y)$ I don't…
usual me
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Defining an inductive set

I'm having some difficulties solving an induction task. Here is the task i'm working on: Give an inductive definition of the given language below: $\{(ab)^n\mid n\in\{0,1,2,\dots\}\} = \{\Lambda,ab,abab,ababab,...\}$ I'm very new to induction.…
Dabbish
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Proof of expression by induction

Hello I am trying to solve that the following expression is true for all positive integers n: $$(n+1)(n+2)\cdots(2n) = 2^n \cdot 1 \cdot 3 \cdot 5\cdot ... \cdot(2n-1).$$ I know that this question needs to be proven by inductions. Please give me…
user92821
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Prove that there exist a pal number with n digits n>1.

We call a number pal if it doesn't have a non zero digit and the sum of the squares of the digits is a perfect square.For example 122 and 34 are pal but 302 and 12 are not pal.Prove that there exist a pal number with n digits n>1. Also this is same…
maths lover
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Is This Proof For $a_nx^n+a_{n-1}x^{n-1}+...+a_1x^1+a_0=0\Rightarrow a_n=a_{n-1}=...a_1=a_0=0$, $\forall n\forall x$ Okay?

Base Case $n=1$: if $ax+b=0$ for all values of $x$, then $a=b=0$ \begin{align} ax+b=0\\ (0)+b=0\\ b=0\\\\ ax+(0)=0\\ ax=0\\ a(1)=0\\ a=0 \end{align} Inductive Step: if $(a_nx^n+a_{n-1}x^{n-1}+...+a_1x^1+a_0=0)\Rightarrow(a_n=a_{n-1}=...=a_0=0)$ for…
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Prove by induction that $\cos\frac{90^\circ}{2^n}=\frac 12\sqrt{2+\sqrt{2+\sqrt{2+\sqrt{...\sqrt{2}}}}}$

I have a little problem. So I am ask to prove this identity by induction for $n\geq 1$ $$\cos\frac{90^\circ}{2^n}=\frac 12\sqrt{2+\sqrt{2+\sqrt{2+\sqrt{...\sqrt{2}}}}}$$ which is relatively straigthforward if you just use regular weak induction and…
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Using a theorem proved inductively to go "downards"

I'm going through Lang's "Basic Mathematics", and one of the exercises is to prove that if $0 < a < b$ for $a, b \in \Bbb{R}$ then $a^{1\over{n}} < b^{1\over{n}}.$ Earlier we were asked to prove that $a^{n} < b^{n}$ with the same assumptions. I've…
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Prove by mathematical induction that $(7n + 1)6^n + (−1)^{n+1}$ is divisible by $49$ for all $n \in \mathbb{Z}^+$.

Here is my solution so far: Inductive step: Assume $P(k)$ is true, i.e. $(7k+1)6^k+(-1)^{k+1} = 49q $, $q$ belong to $z(IH)$ when $n = k + 1$: $$P(k + 1) = 49 \mid (7(k+1)+1)6^{k+1}+(-1)^{k+1}$$ $$ = 49 \mid (7k+7+1)6^{k+1}+(-1)^{k+1}$$ $$ = 49 \mid…
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proving statements with 3 variables by inducting only on one variable

I came across an exercise which asks us to prove by induction a statement that has 3 variables. The exercise provides a hint that we should induct on one variable, and fix the other two variables. Question: Why is it valid and sufficient to induct…
Penelope
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Incomplete math induction

Making a proof for $n>7$ $$2^n>n^2+4n+5$$ Step 1 For $$n=7$$ $$2^7=128>7^2+4(7)+5=82$$ It is TRUE for $n=7$ Step 2 Inductive Hypotesis: It must be true for $n=k$ $$2^k>k^2+4k+5$$ Step 3 3.1: $$2^{k+1}>(k+1)^2+4(k+1)+5$$ But, after this it was said…
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Given $(12/11)^{10}=2.3872$, prove for $n\ge 11$ that $(1+1/n)^n< 3(1-1/n)$

$b^{n+1}$ - $a^{n+1}$ > $(n+1)*a^n*(b-a)$ if b > a > 0 $b^{n+1}$ > $[(n+1)*(b-a) + a]*a^n$ let $b=1+1/n; a=1+1/(n+1)$ then $(1+1/n)^{n+1}$ > $[(n+1)*(1/n-1/(n+1)) + 1 + 1/(n+1)]*(1+1/(n+1))^n$ $(1+1/n)^{n+1}$ > $[1+1/n +…
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How foundational is the theory of mathematical induction?

I’m not sure if this is a redundant question. How does one prove that induction works? Is it axiomatic? Do we simply assume that applying the theory mathematical induction “works”? I understand how induction is used to solve problems, but I’m not…
Ethan
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Proving $n^{2} > n + 1$ using Induction

Suppose $$n^{2} = n + 1, n \geq 2$$ Prove using induction. Inductionstart: $$n_{0} = 2$$ Therefore 4 > 3 and the induction start holds. Inductionstep: $$(n + 1)^{2} = n + 2$$ $$n^{2} + 2n + 2 > n + 2$$ Question: Is it okay to just drop the $n^{2}$…