Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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Why/when is more than one base case needed in mathematical induction?

I've recently started studying mathematical induction and came across this proof:Could someone please explain to me why 10 base cases are necessary? When is more than one base case necessary?
Jules
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Attempt to prove an inequality by induction

I am trying to prove an inequality by induction which is as follows: $$\frac{(2n)!}{2^{2n}\cdot (n!)^2} \le \frac{1}{\sqrt{3n + 1}}$$ Base Case, i.e, for n =1, $$\frac{(2(1))!}{2^{2(1)}\cdot ((1)!)^2} \le \frac{1}{\sqrt{3(1) + 1}}$$ $$\implies…
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Applying mathematical induction to a statement involving two integers

$ \newcommand{\N}{\mathbb{N}} $ Let $R$ be a transitive binary relation on $X$ and $(x_n)_{n\in\N}$ be a sequence in $X$. Claim: If $\forall n \in \N: x_n R x_{n+1}$, $$ \forall m, n \in \N: [m < n \to x_m R x_n] $$ Attempted proof: Let $m \in \N$.…
Hermis14
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General term of a range

I started to solve a task and I did it. Tasks says:Find the currence formula of the range with these terms:$1,2,4,8 \dots$ I found it: $$X_1=1,X_{n+1}=1+X_1+X_2+\dots+X_n, n\ge1.$$ Now I'm trying to prove with mathematical induction that the…
Student
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Question abut the ambiguity of a maths problem.

I am trying to prove by induction that: $$1^3-2^3 +\cdots+n^3=(1+2+\cdots+n)^2 $$ This was a problem from a practice worksheet, but I don't understand how to interpret the LHS. Is the following correct: $$1^3-2^3+3^3-4^3+5^3-6^3+\cdots+n^3$$ Or…
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Use Principle of Mathematical Induction to show that for all $n\:\in \mathbb{N}$, $a_n=2^{n+2}\cdot 5^{2n+1}+3^{n+2}\cdot 2^{2n+1}$ is divisible by 19

Here's what I did: Base Case: $n = 1$, $2^3*5^3+3^3*2^3$ = $1216$ = $19(64)$ Induction Hypothesis (IH): $a_k=2^{k+2}\cdot 5^{2k+1}+3^{k+2}\cdot 2^{2k+1}$ for some $k\:\in \mathbb{N}$. Inductive Step: $a_{k+1}=2^{\left(k+1\right)+2}\cdot…
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Proving that expression can be expressed as a sum of $3n-1$ natural square numbers that are bigger than one

$n$ is a natural number. Prove that $(2n+1)^3 - 2$ can be expressed as sum of $3n - 1$ natural square numbers, which are bigger than one. Is this a valid proof? Showing that $((4+1)^3 - 2) - ((2+1)^3 - 2)=98= 3^2 + 5^2 + 8^2$ can be expressed as a…
prapola
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On some subtleties about different principles of mathematical induction?

I'm reading Gallian's "Contemporary Abstract Algebra", here there are the following principles of mathematical induction from the aforementioned book: Now, there is this proof of the fundamental theorem of arithmetic: And then there is…
Red Banana
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Explicit formula and induction for $a_{n+1} = 3a_n-8$ with $a_1=4$.

Let $a_1 = 4$. Let, for each natural number $n$, $a_{n+1} = 3a_n-8$. Devise an explicit formula for $a_n$, and finally use induction to prove it. Upon cursory inspection, I noticed that $a_2 = 3(4) - 8 = 4$. This clearly creates an infinite loop;…
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Prove $k^7/7 + k^5/5 + 2k^3/3 - k/105$ is an integer

I tried to prove this using induction. Let $k=1$; then the equation gives $$1/7 + 1/5 +2/3 – 1/105 = 105/105 = 1,$$ which is an integer. So it is true for $k=1$. Now let it be true for $n>k$. This gives $$105|(15n^7 + 21n^5 + 70n^3 – n).$$ For…
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Mathematical Induction with Inequalities

$ P(n) = n < 3^n - 4 $ for all $ n \ge 2$ Base case: $2 < 3^2 - 4$ $2 < 5$ Inductive step: Assume true for $n = k$, show true for $n = k + 1$ That is, assume $k < 3^{k} - 4$, and show $k + 1 < 3^{k + 1} - 4$ So, (This is where I might be wrong) $k +…
ryan
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Mathematical Induction: Can I assume that $P(k-1)$ is also true in the induction hypothesis?

Suppose that $y \in \mathbb{R}$, $y \neq 0$ and $y + \frac{1}{y} \in \mathbb{Z}$. Prove using mathematical induction that $y^{n} + \frac{1}{y^{n}}$ is an integer for all $n \geq 1$. Basis step: The statement is true for $n=1$ since: $y^{1} +…
Andy
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general question about infinity induction

I'm a computer science student and during the lecture, the lecturer prove that a set $\cup_{n=0}^\infty A_n \subseteq B$ by induction on $n$. i.e $\forall n$ $A_n \subseteq B$ I remember from my mathematic for computer science that kind of…
OriFrid
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Question about verification of the validity of the method of induction

Say whether the following verification of the method of induction is valid or not? Proof: We have to prove that if $A(1)$ $(∀n)[A(n) ⇒ A(n + 1)]$ then $(∀n)A(n)$. We argue by contradiction. Suppose the conclusion is false. Then there will be a…
maxloo
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To prove the following statement by induction for positive nature number n.

There are both $n$ and $k$ in this formula and I don’t know how to prove it. Because in this case I cannot split the summation into parts contains the assumption. $$\sum_{k=1}^n \frac{1}{(2k-1)2k} = \sum_{k=1}^n \frac{1}{n+k}$$ My basic case is…