Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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Proof by strong Induction for a recurrence

We have a sequence of $a_n = a_{n-3}+a_{n-2}+a_{n-1} \text{ where } a_{1} = a_{2} =a_{3} = 1$ for all $n\ge 4$. Prove $a_n < 2^n$ is true for all positive integers $n$. What I have done so far is starting with the inductive hypothesis because this…
DippyDog
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After thinking for quite a bit, I haven't been able to completely solve this induction question.

Can L tilings be created for L shaped structure (such that the L tilings are in fact trominoes). It seems to not be such a simple question to answer! Though their may be multiple ways of answering the same.
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Proving throught induction

How do I prove the following inquation using induction? $2^n>1+n\sqrt{2^{n-1}}$ , $n\geq 2$ I did the base case, but I'm stuck at the induction process. The induction: $2^{k+1}>1+(k+1)\sqrt{2^{k}}$ Now I used the hipothesis to prove the…
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Problem understanding fallacious argument on Courant/Robbins's "What is Mathematics"?

I've been reading Courant/Robbins' "What is Mathematics?" The first time they mentions $a),b)$ is here: In another section of the book, he points out there is an alternative formulation: Now here: I don't see what is the fallacy here: He…
Red Banana
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How do I prove that if $n$ is greater or equal to $4$, then $(2n)!$ is greater than or equal to $10^n$?

I used the method of induction to prove this. For the basis step, when $n=4$, the statement is $[2(4)]!≥10^4$ which is the same as $40320≥10000$ which is true. Next, for the inductive step, we show $\mathrm{S}_k$ implies $\mathrm{S}_{k+1}$ for some…
Kelly
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Prove by induction that for every $n \geq 1$, every non-empty ternary tree of height n has at most $(3^n − 1)/2$ nodes.

A ternary tree is a tree where each node has at most three children. Prove that for every $n \geq 1$, every non-empty ternary tree of height $n$ has at most $\dfrac{(3^n − 1)}{2}$ nodes. I am confused what to do here, can someone explain me the…
goofy2
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Prove by induction $2\left(n+1\right)\leq\left(n+2\right)^{2}$

Prove by induction $2\left(n+1\right)\leq\left(n+2\right)^{2}$ Case $S(1)$ is true: $$2((1)+2)\leq((1)+2)^{2}$$ $$6\leq9$$ Case $S(n)$ is true for all $n=1,2,...$ $$2(n+2)\leq(n+2)^{2}(i)$$ Case $S\left(n+1\right)$ $$2(n+3)\leq(n+3)^{2}(ii)$$ From…
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Prove by induction that $\frac{1}{2n}\leq\frac{1\text{·}3\cdot5\text{·}\ldots\text{·}(2n-1)}{2+4+6+\ldots+2n}$

What would be the right way to solve this by induction proof? $$\frac{1}{2n}\leq\frac{1\text{·}3\cdot5\text{·}\ldots\text{·}(2n-1)}{2+4+6+\ldots+2n}$$ This is what I've done (reference…
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How to use induction to prove this argument?

It is obvious that this grammar will always return an equal number of both a's and b's. But I was wondering how to prove it using induction? I understand induction, but I was finding it hard to apply to this situation. The ε character denotes an…
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Example for mathematical induction

Currently I am on mathematical induction and I've faced problem that I simply don't know where to even start and I can't find any examples that I can go on with, so just to clarify I am asking you for example with solution of similar task. The task…
str1ng
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Prove $\sin((2n+1)x)$ function by induction

Can someone help me prove the following by mathematical induction: $$\sin((2n+1)x)=\sin(x)(1+2 \sum_{k=1}^{n} \cos(2kx))$$ I was told to use induction on $n$; however I keep getting stuck. Any help would be greatly appreciated!
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$5^n -4n-1$ is divisible by 16

Checking the notes of a proof-based course I encountered this exercise. $5^n -4n-1$ is divisible by $16$ for every natural $n>0$. I'm stuck with this problem. Help me, please Update: I already solved this problem
user926356
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Show using Bernoulli inequality approach (using induction, & transitivity) $2^n \ge n^2, \ \ \forall n\ge 4, n\in \mathbb{N}$.

It is given in the book by John B. Reade, titled: Introduction to Mathematical Analysis; on pg. 7; to prove the inequality $$2^n \ge n^2, \ \ \forall n\ge 4, n\in \mathbb{N}.$$ It states that has distilled the proof using induction, & transitivity…
jiten
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Is mathematical induction necessary in this situation?

I was reading "Number Theory" by George E. Andrews. On P.17, where he proves that for each pair of positive integers a,b, gcd(a,b) uniquely exists, I came up with a question. The approach he used is probably the most common one, that is, to make…
Tengu
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Induction proof [ little-o notation ]

I have to prove that $ 2^n = o(n!) $, that is, $ \forall c \gt 0 \quad \exists$ $ n_0 \in \mathbb N$ such that $ \forall n \ge n_0$ we have $ 2^n \lt c.n! $ Well, this is what I did so far: First I proved, by induction in $n$, that $ 2^n \lt c.n! $…