Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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Proof by induction, induction step

I am trying to prove $$ \sum_{k=1}^n k2^{k-1} = 1+(n-1)2^n $$ I proved the base case with $n = 1$. I am having trouble proving the induction step. I know I need to prove for $n = n +1$ so I got $$ \sum_{k=1}^n k2^{k-1}+(k+1)2^{(k+1)-1} =…
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Prove by induction that this sum is not a natural number.

Prove by induction that $1+\frac{1}{2}+\frac{1}{3} +...+\frac{1}{n}$ for any $1
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Question Proof By Induction (One Step)

I'm self studying proof by induction and have a question about this one step for this question. I have attached the solution and question below. How does one know that $kx^2\ge0$ ? Thank you so much!
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Direct proof of the existence of Strong Induction using the Well Ordering Principle

I'm asked to Deduce the alternate form of PMI from WO as a homework problem. To me, this sounds as if I should be doing some form of direct proof of its existence, however, every proof I see that the basic form of PMI follows from WO uses a proof by…
Mirrana
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Prove by Induction AM-GM

Suppose that $a,b \in \mathbb{R}$ are positive. Prove that: $$\sqrt{ab} \leq \frac{a + b}{2}$$ Note: This inequality is known as the inequality between arithmetic mean, $\frac{a + b}{2}$, and geometric mean, $\sqrt{ab}$, in short, the am-gm…
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proof by induction in worded example

I'm trying to answer the following question: The boxes Banana Ltd. uses to ship bananas come in two sizes, one that holds three bananas and one that holds five bananas. The company promises to ship at least as many bananas as you order. Show…
bawse
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Show inequality of recursive defined exponantial function.

Given the following function: $f(1) = 2$ $f(x+1) = 2^{f(x)}$ Show that $f(i) > f(i-1)^{i-1}$. Starting with some $i > i_0$. Intuitively I can easily see why this is so. Basically $f(x) = 2^{2^{2^{2^{2\dots}}}}$ where there is an $x$ number of…
Ligia24
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Why does the conclusion of induction proofs hold even when the base case is greater than $1$?

The principle of mathematical induction states that if $X\subseteq \mathbb{N}$ satisfying $1\in X$ and if $k\in X$ for all $k
user265675
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Proof by Induction for Natural Numbers

Show that if the statement $$1 + 2 + 2^{2} + ... + 2^{n - 1} = 2^{n}$$ is assumed to be true for some $n,$ then it can be proved to be true for $n + 1.$ Is the statement true for all $n$? Intuitively, then I don't think it holds for all $n.$
user269751
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Use Proof of Induction to prove $\sum_{k=1}^{2n} (-1)^k k = n$

Base Case: \begin{eqnarray*} \sum_{k=1}^{2n} (-1)^k k = n\\ (-1)^1 (1) + (-1)^2(2) &=&1 \\ 1=1 \end{eqnarray*} Inductive Step: For this step we must prove that \begin{eqnarray*} \sum_{k=1}^{2n} (-1)^k k = n \Rightarrow \sum_{k=1}^{2(n+1)} (-1)^k…
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Prove that $n^{(n+1)} > (n+1)^{n}$ when $n\geq 3$

Firstly, for $n=3$, $$3^4 > 4^3$$. Secondly, $(n+1)^{(n+2)} > (n+2)^{(n+1)}$ Now I'm stuck.
Mex
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Induction proof.

Homework question, so just a pointer would be nice, for starters. I'm trying to prove $2 \mid 5^{2n} - 3^{2n}$ by induction. I use $n=0$ as the base step, and assume $5^{2n} - 3^{2n} = 2k$ as my inductive hypothesis. Then for the inductive step I…
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Proof by induction for "sum-of"

Prove that for all $n \ge 1$: $$\sum_{k=1}^n \frac{1}{k(k+1)} = \frac{n}{n+1}$$ What I have done currently: Proved that theorem holds for the base case where n=1. Then: Assume that $P(n)$ is true. Now to prove that $P(n+1)$ is…
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Discrete mathematics question

$$(n+1)^2+(n+2)^2+(n+3)^2+\dots+(2n)^2=\frac{n(2n+1)(7n+1)}{6}$$ Prove the statement using mathematical induction.
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The pattern in mathematical induction proofs

When given a statement to be proven by mathmatical induction the statement tends to look like this $1 + 2 + 3 + \dots + n = \frac{n(n+1)}{2}$ so going about the proof. 1) Prove the base case $\frac{1\times(1+1)}{2} = 1$ 2) Prove the inductive…