Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

10150 questions
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prime numbers and natural numbers

Prove that $n^4+4^n$ is never prime. Here $n$ is any natural number greater than $1$. I have tried by induction hypothesis but to no avail. Can it be done by considering cases when $n$ is odd and when it is even?
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Prove $25^n>6^n$ using induction

This seem too simple that I cant even break this down.. Base case: For $n=1$, we have: LHS: $25^1=25$; RHS: $6^1$ So LHS$>$RHS, holds. Inductive, hypothesis: Assume $25^k>6^k$ for some $n=k>=1$ Inductive step: We nee to show that $k+1$ holds, that…
lucidgold
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Induction proof for the sum 1+2+4+8+...

I think that the sum 1+2+4+8+16+32+...+n is equal to 2n-1. At least it has worked on all the cases I've tried with, but I can't manage to prove it using induction. I am a newbie when it comes to proofs by induction, so am I doing the induction part…
user265554
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How to prove $\sum_{k=n}^{2n} k = 3 \sum_{k=1}^n k $ with complete induction?

I was trying to prove this. Have problems to "pull apart" the first sum to put it down to the induction base (n - 1). Base and step are otherwise clear. Could you please help me?
isindia
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$(|x_1|+|x_2|+...+|x_n|)$ vs $\sqrt{(|x_1|^2+|x_2|^2+...+|x_n|^2)}$, which is larger and why?

Actually, I know which is larger. Is there some kind of rule that states that the square root is less or equal to the first expression? ** My tag is probably incorrect **
Naz
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How to show that $f_{0}f_{1}+f_{1}f_{2}+...+f_{2n-1}f_{2n} = f^{2}_{2n}$

The following problem: The Fibonacci number is denoted by $f_{n}$, show that the following holds when $n$ is a positive integer: $f_{0}f_{1}+f_{1}f_{2}+...+f_{2n-1}f_{2n} = f^{2}_{2n}$ My idea was to do an induction proof, which holds for $n$ =…
Fill
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factorial proof by induction

So I have an induction proof that, for some reason, doesn't work after a certain point when I keep trying it. Likely I'm not adding the next term correctly but I don't know for sure. Question is: If n∈N, then…
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General Derivation and PMI--Why Bother?

Why is it that when we derive, say, a closed form to the series $1+2+\dotsc+n$, which is $\frac{n(n+1)}{2}$, it is almost habitual to do a proof by induction on the equation? If the $n$ was arbitrarily chosen at the beginning of the series, and then…
J. Dunivin
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Is Minimal counterexample proof just induction in disguise?

Since basically what we do is we prove that p(k)=>p(k+2) or p(k+1)=>p(k+2) and so on by just adding a couple of base steps. Am i right here? That is what it seems to me. Please correct me if i am wrong
Sorfosh
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Inductive step for the Fibonacci sequence

Let $F_{n}$ be a Fibonacci sequence given by $$F_{n}=\begin{cases} 0 & \text{ if } n=0 \\ 1 & \text{ if } n=1 \\ F_{n-1}+F_{n-2} & \text{ if } n\geq 2. \end{cases}$$ I was asked to prove that $(3/2)^{n-1}\leq F_{n}$ holds for all $n\geq 6$. I fail…
UnknownW
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Clarify worked example on induction with inequality

I'm reading through example #3 on Purplemath. I don't understand the reasoning behind the line I marked $\dagger$ and why the underlined term, $\underline{2^k}$ gets added!? I'm rewriting the example: (*) Prove that for $n \geq 5, 4n < 2^n$. This…
saner
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Proof by induction $\frac{1}{1^2} + \frac{1}{2^2} + \cdots + \frac{1}{n^2} < 2$

Proof by induction $\frac{1}{1^2} + \frac{1}{2^2} + \cdots + \frac{1}{n^2} < 2 \ \ \ n \in \mathbb{N}$ So for $n=1$ $$ 1 < 2$$ For $n > 1$ Assumption: $$\frac{1}{1^2} + \frac{1}{2^2} + \cdots + \frac{1}{n^2} < 2$$ Hypothesis (inductive…
tomtom
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Proof a Sum with real numbers

I have to prove with Induction that: $ \sum_{i=1}^n a^{i-1} = \frac{a^n -1 }{a-1}$ where $a \in R $ \ {0,1} with $a^0$ = 1 In the first induction step I get to divide by 0, because for a=1 it's 1-1. Well I think I didn't quite understand the…
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Use induction to prove that $a^n + b^n \leq (a+b)^n$

I am doing some exercises in proving things and I am stuck on this proof: $a^n + b^n \leq (a+b)^n$, $a,b > 0$, for every $n > 0$. I start with $n = 1$: $a^1 + b^1 \leq (a+b)^1$. Then I assume that $a^n + b^n \leq (a+b)^n$ is true and need to show…
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Prove using induction / Strong induction

I have a problem: Let $a_0=0, a_1=1$, and let $a_{n+2}=6a_{n+1}-9a_n$ for $n\geq 0$. Prove that $a_n=n\cdot 3^{n-1}$ for all $n\geq 0$. And I am assuming that this can be solved via induction. Only problem is I am not sure how to go about doing…
wbrugato
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