Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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Induction in the Reals?

In most maths textbooks, proofs by induction prove a statement $P_n$ where $n$ usually is in the natural numbers (although I understand that it can be in any discrete collection as long as you prove your base case(s) and prove all cases imply the…
Shuri2060
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$\{a_n\}$ is a sequence of real numbers defined by $a_1=1$, $a_2=2$, $a_3=3$ and $a_n=2a_{n-1} - a_{n-3}$

Image of problem: http://d2vlcm61l7u1fs.cloudfront.net/media%2F901%2F9010d0fd-aeea-43bb-a993-9327afc7df9e%2FphpiKWhi5.png Text of problem: $\{a_n\}$ is a sequence of real numbers defined by $a_1=1$, $a_2=2$, $a_3=3$ and $a_n=2a_{n-1} - a_{n-3}$ for…
Darkdub
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Induction Proof $k^2 \times 2^k$

I need help on this proof. I am not able to do it after setting m=m+1. Prove by induction on n that sum of $k^2 \times 2^k$ from $k=1$ to $n$ is equal to $(n^2-2n+3) \times 2^{n+1}-6$ Base case: Let $k=1$ so L.H.S side is $2$ Let $n=1$ so R.H.S side…
Sai N
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Proving correctness of a recursive function of multiplication by induction.

Define multiplication of two numbers y and z as: $$m_c(y,z)=\begin{cases}0&z=0\\m_c\left(cy,\left\lfloor \frac zc\right\rfloor\right)+y(z\mod c)&z\neq 0\end{cases}\tag{$\forall c\geq 2$}$$ Now I need to show that this is correct using induction. It…
RE60K
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Induction on a sequence {$a_n$}

Let a sequence be defined by $a_0=1$ and $a_{n+1}=\sqrt{3a_n+4}$. Prove by inductions that $0\le a_n \le 4$ for all n. For some reason I can't figure out what my hypothesis is? I know my base case is $a_0$ but then what do I assume? Do I isolate…
Alex
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Induction with summation. How to factor out

Hey Everyone, So here is the problem I am currently working on and I have a few questions with what I can factor our of the sigma notation in order to use the IH. Base Case: $1$ is the base case $1 = 1$ IH: Basically Restate the Question WTP: …
k9b
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Prove by mathematical induction.

TO BE PROVED: $$ \frac{1}{1^2}+\frac{1}{2^2}+\frac{1}{3^2}+\dots \frac{1}{n^2}<2 $$ Please prove this by mathematical induction only. My approach: I already proved it through graphs but i have to prove it through mathematical induction. Prove this…
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Show that for each $n \geq 2$, $\left(1 - \frac{1}{4}\right)\left(1 - \frac{1}{9}\right) \cdots \left(1 - \frac{1}{n^2}\right) = \frac{n + 1}{2n}$

Need to show that for each $n \in \mathbb{N}$, with $n \geq 2$, $$\left(1 - \frac{1}{4}\right)\left(1 - \frac{1}{9}\right) \cdots \left(1 - \frac{1}{n^2}\right) = \frac{n + 1}{2n}$$ How to start the proof by induction? Is there any way to show this?
Ryu
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'Mathematical Induction'

Use mathematical induction to prove that $4^n -3^n + 1 = 7a_{n-1} – 12a_{n-2} + 6$ with $n \ge 3$ with the initial condition $a_1 = 2$ and $a_2 = 8$ . Given that $a_n = 4^n -3^n + 1$. I am confused at the inductive step or $(k+1)$ part.
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Proof by induction to prove an inequality help?

Prove by induction on m where m is an integer, such that m ≥ 2: $$Pm:=\sum_{n=1}^{m} \frac{1}{\sqrt{n}} < 2\sqrt{m}-1$$ I know this holds for the base case since when m=2, P2 is: $$4<3\sqrt2$$ which is clearly true. The inductive hypothesis is…
ky370211
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Use Induction to prove that for all $n \in \mathbb{N}, (x^n + \frac{1}{x^n}) \in \mathbb{Z}$ if $x+\frac{1}{x}\in\mathbb{Z}$.

Assume $x \in \mathbb{R}$ and $(x + \frac{1}{x}) \in \mathbb{Z}$. Use Induction to prove that for all $n \in \mathbb{N},~ (x^n + \frac{1}{x^n}) \in \mathbb{Z}$. I'm not sure how to use the information given to prove the induction step. What I have…
rm120
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Induction with $n+2$

When proving something via induction, is one allowed to do the induction step, showing that the conditions work for $n+2$, instead of $n+1$?
Mac
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$\sum_{k=1}^{n}k(k-\frac{1}{3}) = \frac{n}{6}(an^2+bn+c)$ by induction

Find constants $a$, $b$ and $c$ such that for all $n \in \mathbb{N}$ $~~\sum_{k=1}^{n}k(k-\frac{1}{3}) = \frac{n}{6}(an^2+bn+c)$ Hints: you may want to find $a, b$ and $c$ from the condition that the statement is true for $n = 1, 2, 3$. You…
GGG
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Give a recursive definition for the set T.

I am not sure if math stack exchange is the right place to ask about this but I will ask away. Consider the set T of binary trees that have the following property: For each node in the tree, the heights of that node's left and right subtrees differ…
amundi32
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How do you select base-cases for this proof?

Let $P(n)$ be the statement that a postage of n cents can be formed using just $4$-cent and $7$-cent stamps. Show by mathematical induction that $P(n)$ is true for $n ≥ 18$. Hint: carefully determine what the base cases are. My question is, how do…
lucidgold
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